Quote:Original post by AnonymousTipster
Hi.
I have the current test code:

void ReturnMe(char *value){	value = (char*)malloc(10);}

Which i'm calling like this:

char* stringPtr;stringPtr = 0;	ReturnMe(stringPtr);

So what i'm trying to achieve is to return a pointer to a memory location without using the return value. The reason for this is that in my real problem, I need to return multiple pointers from a function.
The problem is that 'stringPtr' is always 0 and although 'value' is allocated a valid memory address, it isn't returned to 'stringPtr'.
I somehow feel convinced that this would work in C (i've been using GCC for several months now, and I've just moved back to 2005 Express C++).

Hope you can help.
Thanks.

void ReturnMe(char* & value){  value = new char[10];}

Quote:Original post by AnonymousTipster
Out of curiosity, would my original code work in C, GCC or otherwise, or am I being delusional?

Quote:Fair enough, but pointers of any size are expanded to 4byte addresses, regardless of type aren't they?

Quote:Original post by AnonymousTipster
Thanks for your help everyone, it seems I need to learn the difference between pointers and references.

#include <iostream>void incrementUsingReference(int &value){    // Using a reference means we can use value as if it were the variable itself    value++;}void incrementUsingPointer(int *value){    // Dereferences pointer and increments the value stored at the address    (*value)++;}void incrementPointer(int *value){    // No effect - increments the local pointer to the next address    value++;}int main(){    int test = 0;        incrementUsingReference(test);    std::cout << test << std::endl; // "1"    incrementUsingPointer(&test); // We have to take the address of test, too...    std::cout << test << std::endl; // "2"    // Since the function's broken it doesn't matter if we take the address    incrementUsingPointer(&test);     std::cout << test << std::endl; // "2"    // Demonstration:    incrementPointer(test); // Access exception! Invalid pointer used.}

Quote:Out of curiosity, would my original code work in C, GCC or otherwise, or am I being delusional?

Quote:

Quote:Original post by Zahlman's Signature
As a general rule, if you post in For Beginners and your code contains the word 'char', you have a bug. std::string roxors teh big one one one one.

Fair enough, but pointers of any size are expanded to 4byte addresses, regardless of type aren't they?