int j = 0;
for(vector<face*>::iterator i = faces.begin();
i != faces.end();
i++, j++)
{
cout << "deleting " << j << " face\n";
delete (*(i._Myptr));
}
#if _HAS_ITERATOR_DEBUGGING
this->_Orphan_all();//<----------- This line here
#endif /* _HAS_ITERATOR_DEBUGGING */
_Destroy(_Myfirst, _Mylast);
this->_Alval.deallocate(_Myfirst, _Myend - _Myfirst);
}
_Myfirst = 0, _Mylast = 0, _Myend = 0;
}
delete *i; *i=0;Quote:Original post by Drunken_Monkey
Oh, I didn't know you could use the delete operator with iterators, thank god for operator overloading, huh?
for (vector<face*>::iterator i = faces.begin(), int j = 0; i != faces.end(); ++i, ++j){ cout << "Deleting " << j << " face \n"; delete *i;}Quote:Original post by TheUnbelieverQuote:Original post by Drunken_Monkey
Oh, I didn't know you could use the delete operator with iterators, thank god for operator overloading, huh?
Sure, but not in this case.
If you have a vector of pointers, you dereference the iterator and then you apply delete to the pointer you get (the pointer is what the iterator points to, and so is what you get when you dereference the iterator).
The error sounds like you're trying to delete a pointer twice.
What happens with:
*** Source Snippet Removed ***
?
for(vector<face*>::iterator i = faces.begin(); i != faces.end(); i++, j++){ for(vector<face*>::iterator ti = faces.begin(); ti != faces.end(); ti++) { if(*ti == *i) cout << "Face " << j << " is in the list twice!\n"; }}
