i was anwered this before one year this but tuday i cant..?
i think someones hawe enough math knowledge here..
thanks again..
math quiz..? sin(x)=-0.5cos(x)=0.5 x=?
Author
i need a math help.
can anone help me...
sin(x)= -0.5
cos(x)= 0.5
x=?
i need the x value.
if anyone can write a function for this...
it will be prefect thing...
thanks...
i was anwered this before one year this but tuday i cant..?
i think someones hawe enough math knowledge here..
thanks again..
i was anwered this before one year this but tuday i cant..?
i think someones hawe enough math knowledge here..
thanks again..
you don't need a function for this you just need to know the unit circle. and/or need to know how to take the arccos or arcsin.
http://en.wikipedia.org/wiki/Unit_circle
-me
http://en.wikipedia.org/wiki/Unit_circle
-me
arcsin(-1/2) = -p/6
arccos(1/2) = p/3
Of course, you can add any multiple of 2p to these answers.
If you're looking to solve the two equations simultaneously, you'll be here for a long time, as no such solution exists.
Admiral
arccos(1/2) = p/3
Of course, you can add any multiple of 2p to these answers.
If you're looking to solve the two equations simultaneously, you'll be here for a long time, as no such solution exists.
Admiral
There is no such x that satisfies both sin(x) = -0.5 and cos(x) = 0.5. Remember:
sin2(x) + cos2(x) = 1 for all x.
(-0.5)2 + (0.5)2 = 0.5
Therefore there is no x that satisfies those equations.
sin2(x) + cos2(x) = 1 for all x.
(-0.5)2 + (0.5)2 = 0.5
Therefore there is no x that satisfies those equations.
Author
Thanks guys...
its looks like i mistaked somethings...?
also i found the some answers but the answers are not what i wanted...
i guess it's
|OC|=-0.5;
|DC|=0.5;
sin(x)=|DC|
cos(x)=|OC|
heey ... youre right my question is wrong.
i tried to gnereate my own rendering function for opengl...
now can anyone write a function for finding value of x...?
its looks like i mistaked somethings...?
also i found the some answers but the answers are not what i wanted...
i guess it's
|OC|=-0.5;
|DC|=0.5;
sin(x)=|DC|
cos(x)=|OC|
heey ... youre right my question is wrong.
i tried to gnereate my own rendering function for opengl...
now can anyone write a function for finding value of x...?
Quote:Original post by RSC_x
Thanks guys...
its looks like i mistaked somethings...?
also i found the some answers but the answers are not what i wanted...
i guess it's
|OC|=-0.5;
|DC|=0.5;
sin(x)=|DC|
cos(x)=|OC|
heey ... youre right my question is wrong.
i tried to gnereate my own rendering function for opengl...
now can anyone write a function for finding value of x...?
Maybe you're using a different notation, but if |x| is the absolute value of x, then isn't it impossible for |OC| = -0.5?
Also, unless I'm mistaken, that system of equations has no solution either (assuming you meant OC = 0.5 and DC = 0.5).
Quote:Original post by RSC_x
now can anyone write a function for finding value of x...?
For finding x given what? There is only one variable in the system, so you can only specify one constraint, if you want an answer to exist.
Quote:|OC|=-0.5;is overdetermined, and in this case inconsistent.
|DC|=0.5;
sin(x)=|DC|
cos(x)=|OC|
Are you looking to find the polar representation of an arbitrary Cartesian point? (0.5, -0.5) doesn't lie on the unit circle, as it is a distance 1/√2 from the origin. If you're allowed to change the radius of the circle, the new system looks like:
r.sin(x) = -0.5
r.cos(x) = 0.5
which solves to give:
r = 1/√2
x = 3p/4
Admiral
Of course it helps if you are able to work with a right angled triangle with size of the largest side equal to one, and have some idea about normalization.
sin(7*PI/4)
[Edited by - Raghar on May 26, 2007 10:00:12 AM]
sin(7*PI/4)
[Edited by - Raghar on May 26, 2007 10:00:12 AM]
This topic is closed to new replies.
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