bluefox25 100 Report post Posted June 5, 2007 This is my first math class in a LONG time, I am taking college algebra, whatever that means. I am a bit rusty with the process. How do you get rid of the negative sign on a variable? Solve for y so points can be plotted using a T table 3x-y=6 -y= 6-3x or is it 3x-6? ?// now what? It is probably real simple but it escapes me at the moment. Any help appreciated!! 0 Share this post Link to post Share on other sites
smurfkiller 103 Report post Posted June 5, 2007 1: 3x - y = 62: 3x = 6 + y3: 3x - 6 = yans: y = 3x - 6 0 Share this post Link to post Share on other sites
Zanshibumi 334 Report post Posted June 5, 2007 Quote:Original post by bluefox25-y = 6-3x-y * -1 = (6-3x) * -1 0 Share this post Link to post Share on other sites
bluefox25 100 Report post Posted June 5, 2007 Sou would it bey= 3x-6 or y= 6-3xIt makes a difference right? 0 Share this post Link to post Share on other sites
bluefox25 100 Report post Posted June 5, 2007 Quote:Original post by smurfkiller1: 3x - y = 62: 3x = 6 + y3: 3x - 6 = yans: y = 3x - 6I had this in mind but wasn't sure if you could switch the sides of the equation. Like i siad its been awhile.......... 0 Share this post Link to post Share on other sites
Zanshibumi 334 Report post Posted June 5, 2007 Quote:Original post by bluefox25Sou would it bey= 3x-6 or y= 6-3xIt makes a difference right?-y * -1 = (6-3x) * -1 y = (6 * -1) - (3x * -1) y = (-6) - (-3x) y = -6 + 3x y = 3x-6 Introduction to algebra, simplifying equations. 0 Share this post Link to post Share on other sites
bluefox25 100 Report post Posted June 5, 2007 Would this be right?x-4y=5x=5+4yx-5=4yx-5___ = y4So if x = -3,-2,-1,0,1,2,3(-3,-2)(-2,-7/4)(-1,2/3)Come to think of it, this isn't right is it? Canyou have a fraction as coordinate?Maybe it should bey= 1/4x+(-5)? 0 Share this post Link to post Share on other sites
Zanshibumi 334 Report post Posted June 5, 2007 Quote:Original post by bluefox25So if x = -3,-2,-1,0,1,2,3(-3,-2)(-2,-7/4)(-1,2/3)Come to think of it, this isn't right is it?You were doing it just right.(-3,-8/4)(-2,-7/4)(-1,-6/4) //not 2/3( 0,-5/4)( 1,-4/4)( 2,-3/4)... 0 Share this post Link to post Share on other sites
bluefox25 100 Report post Posted June 5, 2007 Thanks!1So I am not totally out of my mind yet!1Wish I hadnt taken this class oer summer4hrs a day for class * 4 days a week = TOO MUCH MATH!!!So there is nno need to reduce the fractions? Any particular reason? 0 Share this post Link to post Share on other sites
bluefox25 100 Report post Posted June 5, 2007 Let see if I can get this one4x-3y=124x=12+3y4x-12=3y4x-12_____ = y3y= 4x-4Am I right? 0 Share this post Link to post Share on other sites
CTar 1134 Report post Posted June 5, 2007 Quote:Original post by bluefox25Let see if I can get this one4x-3y=124x=12+3y4x-12=3y4x-12_____ = y3y= 4x-4Am I right?You do the divison incorrectly. When you have:4x-12=3ythen what you do is divide both sides by 3 and get:(4x-12)/3=3y/3Clearly 3y/3=y, so we have:(4x-12)/3=yWhen we have multiple terms we divide every term seperately so we'll get:4x/3-12/3=ySo:y = 4x/3-4 is the final solution.You need to refresh your arithmetical rules a little if you want to solve it successfully. 0 Share this post Link to post Share on other sites
bluefox25 100 Report post Posted June 5, 2007 If instead of trying to smplfy the equation and if I left it like this: 4x-12_____ = y3then that would acceptable too right like when I had x-5___ = y(in the prev problem)4 0 Share this post Link to post Share on other sites
Zanshibumi 334 Report post Posted June 5, 2007 Quote:Original post by bluefox25Let see if I can get this one4x-3y=124x=12+3y4x-12=3y4x-12_____ = y3y= 4x-4Am I right?The first step you should have followed is divide all by 3;4x - 3y = 12 4x/3 - y = 12/3y = 4x/3 - 4 0 Share this post Link to post Share on other sites
bluefox25 100 Report post Posted June 5, 2007 (-x-x) squared would be ?2x squared? 0 Share this post Link to post Share on other sites
bluefox25 100 Report post Posted June 5, 2007 ok thanx 0 Share this post Link to post Share on other sites
Zanshibumi 334 Report post Posted June 5, 2007 Quote:Original post by bluefox25(-x-x) squared would be ?2x squared?for (x-3)squared:Square of a sum-x-x = 0;[edit] Yeah! I did write that! Now I'll feel stupid for about a month or so![/edit][Edited by - Zanshibumi on June 5, 2007 6:51:37 AM] 0 Share this post Link to post Share on other sites
CTar 1134 Report post Posted June 5, 2007 Quote:Original post by Zanshibumi-x-x = 0;No, that is only the case when x=0. -x-x = -2x.Quote: (-x-x) squared would be ?2x squared?Instead of trying to remember a lot of complicated rules try to consider what you're doing. - x - x must equal -2x, which is a product of two numbers (-2 and x). When squaring a product we can just square its factors separately like so:(-2x)^{2} =(-2)^{2}x^{2} =4x^{2}Remember that when we say 2x we just mean 2 times x. Try to think about what you're doing instead of remembing rules for all kind of stuff. For instance if you've got:(x+2)^{2}How would you expand it? Squaring is simply a multiplication by itself so we have:(x+2)(x+2)To simplify it a little we introduce another identifier, y which we makes equal to (x+2), then we have:(x+2)yWe then multiply into the parantheses:xy+2yWe then expand the y to what it actually stood for:x(x+2)+2(x+2)We then multiply into the parantheses again:xx+2x+2x+2*2Since 2x+2x=4x, 2*2=4 and xx=x^{2} we get:x^{2}+4x+4Simple if you just give it a little thought and know your basic rules. Also you don't really need to introduce the extra identifier y, but I felt it would help show how you can multiply into parantheses even when you multiply by a sum. 0 Share this post Link to post Share on other sites
bluefox25 100 Report post Posted June 5, 2007 Thanx that clarifies things alot. I might just hold off on taking this course over the summer. It is insane, the amount of homework there is. We had about 150 problems due today!! I still have about 10 problems to go in the first section and I still got 3 more sections to go!!And its gona be like that everyday all week long! 0 Share this post Link to post Share on other sites
grhodes_at_work 1385 Report post Posted June 7, 2007 Folks,I've been a bit more relaxed on forum schoolwork policies lately, for various reasons. But, my basic position is still the same. If someone posts a simple academic type problem (e.g., how do i solve this types of questions), that isn't focused on game development, please do not give them the answer! Give them hints to help them to learn how to better solve the problem on their own. My opinion is that giving answers may harm some (though not all) people who might ask.As for whether such posts are allowed in the future, I will continue to make that decision as forum moderator. It will in most cases depend on how the question is asked, amonst other things. 0 Share this post Link to post Share on other sites
Raghar 96 Report post Posted June 7, 2007 Have you listened about sosmath? 0 Share this post Link to post Share on other sites