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Loop Problem

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if (quit != 'n' || quit != 'N' || quit != 'y' || quit != 'Y') {
	cout << "You did not enter a valid option. Please try again, Y for yes and N for no.\n\n";
	quit = end_program();
}
		
No matter what input I use this loop always executes. What I'm trying to do is say if quit does not equal n or N or y or Y then execute the loop, but not for when quit is equal to n, N, y, or Y. Thanks for the help.

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Quote:
Original post by Hammonjj

quit != 'n' || quit != 'N'


This will always be true, no matter what character quit holds (because quit cannot hold two different values at the same time).

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