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Loop Problem

General and Gameplay Programming Programming

Started by Hammonjj June 07, 2007 07:47 PM

5 comments, last by Hammonjj 16 years, 10 months ago

Hammonjj

122

Author

June 07, 2007 07:47 PM

if (quit != 'n' || quit != 'N' || quit != 'y' || quit != 'Y') {
	cout << "You did not enter a valid option. Please try again, Y for yes and N for no.\n\n";
	quit = end_program();
}

No matter what input I use this loop always executes. What I'm trying to do is say if quit does not equal n or N or y or Y then execute the loop, but not for when quit is equal to n, N, y, or Y. Thanks for the help.

James HammondUniversity of ColoradoDepartment of Computer Science

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blaze02

100

June 07, 2007 07:50 PM

Check your logic. You want to "AND" them together.

... quit != 'n' && quit != 'N'...

-------Harmotion - Free 1v1 top-down shooter!Double Jump Studios Blog

Driv3MeFar

1,080

June 07, 2007 09:31 PM

Further reading: De Morgan's laws.

iMalc

2,466

June 08, 2007 01:33 AM

Loop? What loop?

There is no spoon loop.

"In order to understand recursion, you must first understand recursion."
My website dedicated to sorting algorithms

12,313

June 08, 2007 02:07 AM

Judging by that minimal snippet of code, you also want to change your "if" to "while".

DevFred

840

June 08, 2007 08:11 AM

Quote:Original post by Hammonjj
quit != 'n' || quit != 'N'

This will always be true, no matter what character quit holds (because quit cannot hold two different values at the same time).

Hammonjj

122

Author

June 08, 2007 10:13 AM

Thanks!

After seeing what I did wrong I hit myself. I feel kind of like an idiot.

James HammondUniversity of ColoradoDepartment of Computer Science

This topic is closed to new replies.

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