Zeraan 317 Report post Posted August 1, 2007 Yes, it's for my physics class. I've tried googling this up, and studied the book. But I just DON'T get it. I understand that pressure is p = p0 + (density of liquid)(gravity)(depth in meters). But when faced with a question, I got stumped. I don't want an answer, I want a clear explanation of why and how it is so. Okay, the answer is 2440 kg (from back of the book), just to clarify things up. The question is: A 1.0 m-diameter vat of liquid is 2.0 m deep. The pressure at bottom of the vat is 1.3 atm (or 131,690 Pascals). What is the mass of the liquid in the vat? Where do I start? I'm stumped. Any help is appreciated! I feel rather dumb, as I know this has to be a simple question. 0 Share this post Link to post Share on other sites
Nypyren 12061 Report post Posted August 1, 2007 The solution to all physics problems is to know all of the equations that include terms that you know, and terms that you need to know, then chain the equations together to get the answer. Basically all you need to memorize are which equations have terms that can help you out and the rest is usually simple algebra (until you get to magnetic fields in calculus-based physics class. SCREW magnetic fields.)You could probably even make a computer program that does equation lookups for you...HMM***** SPOILERS BELOW *****Step 1: Insert all known constants into the pressure equation and solve for density. Your story problem doesn't explicitly state what the pressure at the top of the vat is, but if you think about the name of the units of measure you're using you'll figure it out.Step 2: Find volume of cylinder (easy)Step 3: Use Mass = Volume * Density to solve for mass. 0 Share this post Link to post Share on other sites
Zeraan 317 Report post Posted August 1, 2007 Okay, I think I follow.I know that p0 is the atmospheric pressure (top of vat), so it's 1 atm. So, if I remove that from the pressure, I get .3 atm for the remaining pressure. Then I have to convert that to pascals.It'd be 30390 pascals, then dividing that by (9.8*2) will yield 1550.51.then multiplying it by the volume (2 meters in height times pi times radius squared which is .5 meter) yields... 2435.54!!!! Rounding it to 3 significant figures gives 2440 kg! Thanks so much! 0 Share this post Link to post Share on other sites
grhodes_at_work 1385 Report post Posted August 3, 2007 Quote:Original post by ZeraanYes, it's for my physics class....I don't want an answer, I want a clear explanation of why and how it is so.Thank you so much for these comments, and for following my forum policies on schoolwork. I appreciate it! 0 Share this post Link to post Share on other sites
Darkstrike 206 Report post Posted August 4, 2007 It may be useful to look at this from a slightly different POV: you have 0,3 atm extra pressure on the bottom of the vat, having area 0,785. This implies a total force of 23,9 thousand Newtons acting on the said bottom, all due to the liquid sitting above it; so the liquid's weight is 23,9 Newtons, mass is 2430 kg (sorry about the sloppy rounding). Of course, it's the same way one gets the formula you quoted, but sometimes it's easier to handle problems from this direction. 0 Share this post Link to post Share on other sites