tile math problem
Author
I have a 64x64 texture that has 4 32x32 textures on it.
I have a number, based on a timer, that goes from 1 to 4 that represents the region I want to draw. I need to tell a draw method the coordinates of a 32/32 region of this texture to use.
I figured out the x coordinate pattern :
int x1 = ((region + 1) % 2) * 32;
I cant for the life of me figure out the Y pattern.
Heres an input / output chart (r = region)
r x1 y1 x2 y2
1 0 0 32 32
2 32 0 32 32
3 0 32 32 64
4 32 32 64 64
Its the y1 region I cant figure out.
Your current x calculation is wrong. It would get you the opposite region to the one you wanted (so region 0 would get you r1, region 1 would get you r0).
Alan
// region must be an integerint x1 = (region % 2) * 32;int y1 = (region / 2) * 32;Alan
I think that using a zero-based index would simplify things a little bit -
x1 = (region % HORIZONTAL_TILES) * TILE_WIDTH
x2 = x1 + TILE_WIDTH
y1 = (region / HORIZONTAL_TILES) * TILE_HEIGHT (integer division will truncate the remainder of this division)
y2 = y1 + TILE_HEIGHT
this would give (I think...)
r x1 y1 x2 y2
0 0 0 32 32
1 32 0 32 32
2 0 32 32 64
3 32 32 64 64
If your timer values have to be 1-4, you could just subtract 1 from the timer value before using as a region index.
x1 = (region % HORIZONTAL_TILES) * TILE_WIDTH
x2 = x1 + TILE_WIDTH
y1 = (region / HORIZONTAL_TILES) * TILE_HEIGHT (integer division will truncate the remainder of this division)
y2 = y1 + TILE_HEIGHT
this would give (I think...)
r x1 y1 x2 y2
0 0 0 32 32
1 32 0 32 32
2 0 32 32 64
3 32 32 64 64
If your timer values have to be 1-4, you could just subtract 1 from the timer value before using as a region index.
I also recommend using r from 0..3 instead of from 1..4 - it makes these kinds of things much easier. Here is a way of getting your numbers using bit shifting:
for( int r = 0; r < 4; ++r )
{
int x1 = ( r & 1 ) << 5;
int y1 = ( r & 2 ) << 4;
int x2 = ( ( ( r & ( r >> 1 ) ) & 1 ) + 1 ) << 5;
int y2 = y1 + 32;
printf( "r=%d, x1=%2d, y1=%2d, x2=%2d, y2=%2d\n", r, x1, y1, x2, y2 );
}
gives
r=0, x1= 0, y1= 0, x2=32, y2=32
r=1, x1=32, y1= 0, x2=32, y2=32
r=2, x1= 0, y1=32, x2=32, y2=64
r=3, x1=32, y1=32, x2=64, y2=64
for( int r = 0; r < 4; ++r )
{
int x1 = ( r & 1 ) << 5;
int y1 = ( r & 2 ) << 4;
int x2 = ( ( ( r & ( r >> 1 ) ) & 1 ) + 1 ) << 5;
int y2 = y1 + 32;
printf( "r=%d, x1=%2d, y1=%2d, x2=%2d, y2=%2d\n", r, x1, y1, x2, y2 );
}
gives
r=0, x1= 0, y1= 0, x2=32, y2=32
r=1, x1=32, y1= 0, x2=32, y2=32
r=2, x1= 0, y1=32, x2=32, y2=64
r=3, x1=32, y1=32, x2=64, y2=64
This topic is closed to new replies.
Advertisement
Popular Topics
Advertisement
