Sign in to follow this  

help me out

Recommended Posts

ok, do the mclauren series then.

f(x) = x^(1/2)
f`(x) = +(1/2)x^(-1/2)
f(2)(x)= -(1/4)x^(-3/2)
f(3)(x)= +(1/8)x^(-5/2)

.. plug in 0 for x, and then do out the mclauren series and your good

also, newton's binomial series is good
also, you can use any non linear solver you want, like newtons method or bisection method.

Share this post

Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now

Sign in to follow this