int num = 55;
wchar_t *wchar = new wchar_t[3];
_itow_s(num, wchar, 3, 10);
std::cout << *wchar;
_itow_s problems
Author
Hey, I'm attempting to convert from an int to a wchar_t like so:
the code compiles fine but when i run it, it outputs the number 53 instead of 55, howcome?
thanks
53 is the ASCII value for '5'. Because you're sending a Unicode character to an non-Unicode stream it actually gets treated as an int. You're also trying to print a single character rather than the whole string.
You'll get what you expect if you change it to 'std::wcout << wchar;'. You might also consider using wstringstream or boost::lexical_cast instead of _itow_s.
You'll get what you expect if you change it to 'std::wcout << wchar;'. You might also consider using wstringstream or boost::lexical_cast instead of _itow_s.
Because you're printing out the character code of the first L'5'.
int num = 55;std::wstring string = boost::lexical_cast< std::wstring >(num);std::wcout << string;int num = 55;wchar_t *wchar = new wchar_t[3];_itow_s(num, wchar, 3, 10);std::wcout << wchar;Use std::wcout with wide characters, and you don't have to dereference C strings to print them out (just make sure they are correctly null terminated).
But, really, you should be using a std::wstring and std::wstringstream.
Author
oh okay cool.
Hmmm... I've never seen the boost namespace before.
What is it exactly and which header do I include to use it?
thanks
Hmmm... I've never seen the boost namespace before.
What is it exactly and which header do I include to use it?
thanks
Quote:Original post by LittleJimmy
Hmmm... I've never seen the boost namespace before.
What is it exactly and which header do I include to use it?
Boost
This topic is closed to new replies.
Advertisement
Popular Topics
Advertisement
