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[c++] overloading operator ()

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Hi, Can anyone tell me if it is possible to overload the call method ()? Heres what I tried: class MyDXDevice { public: IDirect3DDevice9* operator()(void) { return m_device; } private: IDirect3DDevice9* m_device; }; but using MyDXDevice() causes: error C2064: term does not evaluate to a function taking 0 arguments Thanks all! Simon

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Calling MyDXDevice() calls the constructor, not operator(). See example:
#include <iostream>

using namespace std;

class test
{
public:
int operator()() {return 5;};
};

int main()
{
test t;
cout << t() << endl; //works fine. Outputs 5.
cout << test() << endl; //ERROR! Attempting to call the constructor, which does not return a type for which operator<< is defined.
}


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