Quote:From id3v2.3.0 Numbers preceded with $ are hexadecimal. The most significant bit (MSB) of a byte is called 'bit 7'. ... The ID3v2 tag size is encoded with four bytes where the most significant bit (bit 7) is set to zero in every byte, making a total of 28 bits. The zeroed bits are ignored, so a 257 bytes long tag is represented as $00 00 02 01I read those four bytes into an unsigned int right? Then some kind of shift operation? The number is stored big endian; do I 'flip' it before or after processing? (My machine is little endian) I've tried to work it out on paper but I end up with either 192 or 258! Please save my hair! How do I do it?
28bits from 4 bytes?
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Hello all. Once again I'm stuck and pulling out hair trying to work out how to process this number from an mp3 file header:
#include <iostream>unsigned decode(unsigned char *s, unsigned n_bytes) { unsigned result = 0; for(unsigned i=0; i<n_bytes; ++i) result = (result<<7) + s; return result;}int main() { unsigned char s[4]={0,0,2,1}; std::cout << decode(s,4) << std::endl;}The code above will work on machines of any endianness.
You also might want to do a data-integrity check, making sure that the MSB of each byte is indeed 0.
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