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error C2440, char [2] to char?

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char change(char strng[2]) { switch(strng[0]) { case 0: { strng[0]="9"; break; } case 3: { strng[0]="6"; break; } } y does it need to convert? how do i convert it? or is this impossible? as an explanation, this function is taking in a hex value, and testing its values and changing them. Would this even work? I mean i have to test for both characters and numbers.

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I don't know why you get this error message, or which line it is, but I think you should put 6 and 9 between ' intead of " since it's a single character, not a string.

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Quote:
Original post by Dunge
I don't know why you get this error message

actually because "9" has type char[2] which cannot be implicitely converted to char ;)

OP, you may be able to rewirte your function like this:

char change(char strng)
{
switch(strng[0])
{
case 0:
return '9';
case 3:
return '6';
}

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