#include<iostream>
#include<vector>
using namespace std;
void cvector(vector<int> &hammer())
{
for(int i=0;i==2;i++){
cout<<&hammer<<endl;
}
}
int main()
{
vector<int> stuff;
stuff.push_back(1);
stuff.push_back(2);
stuff.push_back(3);
cvector(stuff);
cin.get();
return 0;
}
std::vector as argument
Author
I have been trying to explore my knowledge, however on this i am stumped.
.:The Idea:.
To pass a vector array into a function
.:The Current Code:.
Very Simple.
.:The Problem:.
Nothing comes up. It compiles but the program doesnt appear. task Manager doesnt even show it processing.
Compiler:Dev-Cpp
I have searched a few threads and saw a bit more advanced problem, but not like this one. Awaiting reply.
void cvector(vector<int> &hammer()){ for(int i=0;i==2;i++){ cout<<&hammer<<endl; }}What's the () for after hammer?
How could i == 2 if you just set it to 0?
Step through it in a debugger, you'll be able to debug your program that way.
Author
Original post by RDragon1void cvector(vector<int> &hammer()){ for(int i=0;i==2;i++){ cout<<&hammer<<endl; }}Quote:
What's the () for after hammer?
good point.Quote:
How could i == 2 if you just set it to 0?
because i==2 is testing if it 2 or not. since it is initialized to 0 it would have to make 3 passes through the for(;;) loop.
Ran it through a debugger, and i am pretty sure it didnt see anything wrong.
Quote:Original post by Dv02Quote:
How could i == 2 if you just set it to 0?
because i==2 is testing if it 2 or not. since it is initialized to 0 it would have to make 3 passes through the for(;;) loop.
Exactly. It's initialized to 0. So before it enters the loop, it tests if i == 2, which is false, so it never enters the loop at all.
Author
Quote:Original post by RDragon1Quote:Original post by Dv02Quote:
How could i == 2 if you just set it to 0?
because i==2 is testing if it 2 or not. since it is initialized to 0 it would have to make 3 passes through the for(;;) loop.
Exactly. It's initialized to 0. So before it enters the loop, it tests if i == 2, which is false, so it never enters the loop at all.
I guess before i posted i should have changed it to i!=2. Sorry. Well, i put that in there and same problem. compiles fine, but i dont get a console or visual. also, thx for the lesson
firstly, use vector::size();
Secondly, try doing:
I havent tested this at all fyi
for(int i = 0; i < myVector.size(); i++){}Secondly, try doing:
void cvector(vector<int> &hammer){ for(int i=0;i<hammer->size();i++){ cout<<hammer->at(i)<<endl; }}I havent tested this at all fyi
#include<iostream>#include<vector>using namespace std;void cvector(const vector<int> &hammer) // no need for (), added const since it will not be modified{ for( int i=0; i != hammer.size() ; ++i ){ // check for vec size, not magic numbers, use preincrement when postincrement not needed (forum might not display "plusplus" before i cout<<hammer<<endl; // '&' in front of hammer will give you the address of the variable, not the var itself }}int main(){ vector<int> stuff; stuff.push_back(1); stuff.push_back(2); stuff.push_back(3); cvector(stuff); cin.get(); return 0;}
Author
Quote:Original post by Crazyfool
firstly, use vector::size();for(int i = 0; i < myVector.size(); i++){}
Secondly, try doing:void cvector(vector<int> &hammer){ for(int i=0;i<hammer->size();i++){ cout<<hammer->at(i)<<endl; }}
I havent tested this at all fyi
only error i get is
8 base operand of `->' has non-pointer type `std::vector<int, std::allocator<int> >'
EDIT
I got it to go back to the origional no show by using periods instead of the ->
Author
Thank you guys, my code now works.
also, Thanks for teaching me some lessons about vector.
also, Thanks for teaching me some lessons about vector.
Good to hear, yea sorry my mind has been a bit fuzzy tonight ;p. glad to see you got it working.
This topic is closed to new replies.
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