template <typename T, typename CONT /*= std::vector*/ >
struct Stack{
CONT elem;
};
error: expected type-specifier
error: expected '>'
One template question
Author
It's because std::vector is a templated type too, so you need to specify something for it to template on. For example, template <typename T, typename CONT = std::vector<int> > will work because now the compiler knows 'a vector of what?'
You probably wanted:
template <typename T, typename CONT = std::vector<T> > struct Stack{ CONT elem;};
For std::vector to be considered a complete type it needs its one parameter specified. You might want something like this
And as they say... ninja'd... twice :p
template <typename T, typename CONT = std::vector<T> > struct Stack{ CONT elem;};And as they say... ninja'd... twice :p
Try:
EDIT: Waaaaay too slow [smile]
template <typename T, typename CONT = std::vector<T> > struct Stack{ CONT elem;};EDIT: Waaaaay too slow [smile]
You can do what you want by using template template parameters:
[Edited by - D_Tr on December 5, 2008 10:26:07 AM]
#include <vector>template<typename T, template<typename T, typename Alloc> class CONT = std::vector>struct Stack{ CONT<T, std::allocator<T> > elem;};int main(){ Stack<int, std::vector> s; return 0;}[Edited by - D_Tr on December 5, 2008 10:26:07 AM]
Author
Thanks all understood
I forgot that std::vector does not name a type rather std::vector<SOMETYPE> is a Typename
I forgot that std::vector does not name a type rather std::vector<SOMETYPE> is a Typename
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