char *text[80];char text[][80];yet another pointer question
Author
I want to create an indeterminate array of strings with a length of 80 characters like so:
My first thought is, why?
But anyway...
Why not create a std::vector or std::list of std::strings and just truncate them when you put them into the list.
Overall it would seem more elegant and less fraught with pitfalls.
But anyway...
Why not create a std::vector or std::list of std::strings and just truncate them when you put them into the list.
Overall it would seem more elegant and less fraught with pitfalls.
Warning: I have not tested this code, and honestly it looks potentially deadly [wink]
I think the malloc is incorrect, but something like this may "work". You should now be able to do something like:
arr->str[3][27]
EDIT: This 'works' on gcc 4.2
[Edited by - smc on February 18, 2009 12:45:28 AM]
typedef struct iArr { char str[][80] ;} ;int main(){ int num = 4 ; iArr * arr = (iArr*)malloc( sizeof(iArr) * sizeof(char) * num) ; }I think the malloc is incorrect, but something like this may "work". You should now be able to do something like:
arr->str[3][27]
EDIT: This 'works' on gcc 4.2
[Edited by - smc on February 18, 2009 12:45:28 AM]
Author
Quote:Original post by scratt
Why not create a std::vector or std::list of std::strings and just truncate them when you put them into the list.
because I like to be difficult! hehe nah just joking. well, almost. because I'm using C, not C++ and also because I want to understand the problem better.
you could use the suggested solution above, otherwise, if you would like to stick to c - strings, heres what to do (i think this is what you want):
Then, you can access those strings in the 2d array above by doing the following:
i might not being doing it right, but give it a go (i dont often use 2d arrays)
Hope that helps!
~Reegan
EDIT: Confirmed, i just tested the code and it works for me.
//first [] is the amount of strings (given a value at compile time, i think).//[80] is the possible/allocated length for each string in the array.char text[][80] = { "Hello " , "world! " , "My " , "name is" , "Reegan!" ,};Then, you can access those strings in the 2d array above by doing the following:
std::cout << text[0] << std::endl; //string 0 = Hellostd::cout << text[1] << std::endl; // string 1 = World!std::cout << text[2] << std::endl; // string 2 = Mystd::cout << text[3] << std::endl; // and so on ...std::cout << text[4] << std::endl; // ...i might not being doing it right, but give it a go (i dont often use 2d arrays)
Hope that helps!
~Reegan
EDIT: Confirmed, i just tested the code and it works for me.
Try this:
Hopefully that does the trick!
#define NUMSTRINGS 8char ( *text )[80];text = new char[ NUMSTRINGS ][80];// or call malloc with NUMSTRINGS * 80Hopefully that does the trick!
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