#include <iostream>
using namespace std;
int main(int argc, char *argv[]){
int array1[5][5];
int puts=1;
for(int i=1;i<=5;i++){
for(int j=1;j<=5;j++){
array1[j]=puts;
cout<<array1[j]<<"\t";
puts++;
}
cout<<endl;
}
system("pause");
return 0;
}
2D arrays question ??
Author
sorry if this is a stupid question, but I'm testing out some arrays stuff, and I received this error:
Run-Time Check Failure #2 - Stack around the variable 'array1' was corrupted.
this is the code:
Arrays in programming are (almost?) always 0 based. That is, the first item is at [0] not at [1]
should be
-me
for(int i=1;i<=5;i++) {for(int j=1;j<=5;j++) {should be
for(int i=0;i<5;i++) {for(int j=0;j<5;j++) {-me
Quote:Original post by Palidine
for(int i=0;i<5;i++) {
for(int j=0;j<5;j++) {
You just made it have six terms. It should only be five.
the way it should be put:
for(int i=0;i<4;i++) {for(int j=0;j<4;j++) {
@X19OV1: Palidine's code is fine, it runs from 0 to 4 (not 5, because 5 is not lower than 5, so the loop will bail out there). Your code only runs up to 3.
Quote:Original post by Captain P
Your code only runs up to 3.
How does my code only run up to 3?
Try it. Look at the output:
#include <iostream>int main(int, char **) { for(int j=0;j<4;j++) std::cout << j << std::endl;}
Because j < 4, the only way that is possible it at 3 or less. So it can never reach 4.
theTroll
theTroll
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