char array1[100];
char array2[100];
if (array1 & array2)
doSomething();
for( int i=0; i<100; ++i ){//for each element in the array if( array1 & array2 )//check for overlap at the i'th element break;//stop the loop, we found an overlap}if( i < 100 )//if the loop exited before getting to 100 doSomething();Quote:Original post by Nietsnie
If I try to do something like:if (array1 & array2) doSomething();
(basically checking for overlap in the arrays) the compile throws out an error.
Quote:Original post by Hodgman
*** Source Snippet Removed ***
for(int i = 0; i < 100; ++i){ // for each element in the array if(array1 & array2) // check for overlap at the i'th element { doSomthing(); break; // stop the loop, we found an overlap }}Quote:Original post by DevFredQuote:Original post by Nietsnie
If I try to do something like:if (array1 & array2) doSomething();
(basically checking for overlap in the arrays) the compile throws out an error.
What exactly do you mean by "checking for overlap"? Can you post an example where two arrays overlap and one where they don't?
Quote:Original post by MikeTacularI put the DoSomething out of the loop so the logic of doing the overlap check was separate, but yeah, putting it in the loop is simpler. My bad about overlooking the scope tho!
Why not: *** Source Snippet Removed ***
You're last if statement was using i out of its scope.
Quote:Original post by MortusMaximusNietsnie was ANDing to check for bit-wise overlap (not byte-wise overlap). I assume when expanding this to an entire array Nietsnie still wanted to check for bit-overlap, but who knows...Quote:Original post by DevFred
What exactly do you mean by "checking for overlap"?
What do you need to bitwise AND them for, anyway?
template<typename T, size_t n>bool overlap(T const (&a)[n], T const (&b)[n]){ for (size_t i = 0; i < n; ++i) if (a & b) return true; return false;}
