# Calculate Area in 3D

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Ok, so its easy to calculate are of a triangle when theres no z component. heres my senerio (0, 3, 2) (2, 3, 4) (3, 6, 1) Are the points of the triangle Basicly I calculated the change in x, y, and z and got width = 3, height = 3, depth = 2 I'd like to find the are of this triangle but following the A = 1/2bh wont work because this isn't the triangle's actual height. Its the height of it when its leaning on the z axis. Some how I need to make z = the same value for every vertex and then I can calculate the area.

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The area of a triangle in 3-d is proportional to the length of the cross product of any two of the triangle's edges.

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Any of the two triangles edges. How would I write that? ( in vector form )
I have the sides but I'm not sure how I'd write edges

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Quote:
 Original post by zaneski13Any of the two triangles edges. How would I write that? ( in vector form )I have the sides but I'm not sure how I'd write edges
From any point, take the vectors to the other 2 points. Cross those vectors, and divide its magnitude by 2.

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Rutin
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khawk
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A4L
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