How do you convert from 'const wchar_t *' to 'WCHAR [32]'
Author
Hi,
Trying to figure out a conversion.
I am passing in a std::wstring refrence to a function and then trying to assign it to a D3DXFONT_DESC member.
int CreateFont(std::wstring& name)
{
D3DXFONT_DESC lf.
lf.FaceName = name.ctr();
}
This gives
error C2440: '=' : cannot convert from 'const wchar_t *' to 'WCHAR [32]'
Any suggestions?
Regards
Chad
You need to memcpy or strcpy the string from name.c_str() to the wchar_t array. Remember that lf.FaceName must be a null terminated string!
Quote:Original post by Fox32
You need to memcpy or strcpy the string from name.c_str() to the wchar_t array. Remember that lf.FaceName must be a null terminated string!
You will probably not want to use strcpy() since it is not designed to handle multibyte strings. memcpy() will not null-terminate for you. According to MSDN the function wcscpy() can be used; it has the same signature as strcpy() but takes widechar arguments.
EDIT: And obviously you need to be careful not to overflow the buffer too. :)
Quote: And obviously you need to be careful not to overflow the buffer too. :)
wcscpy_s would solve this problem.
Edit:
errno_t result = wcscpy_s(lf.FaceName, name.ctr());If result is non zero, your name is probably longer than 31 characters and than lf.FaceName isn't modified.
Author
Excuse me if I am a dope but I am trying this and it is not working.
int CreateFont(std::wstring& name)
{
D3DXFONT_DESC lf.
assert(fontName.length() < sizeof(lf.FaceName));
strncpy_s(lf.FaceName, sizeof(lf.FaceName), fontName.c_str(), fontName.length() + 1);
}
error C2664: 'errno_t strncpy_s(char *,rsize_t,const char *,rsize_t)' : cannot convert parameter 1 from 'WCHAR [32]' to 'char *'
Regards
Chad
int CreateFont(std::wstring& name)
{
D3DXFONT_DESC lf.
assert(fontName.length() < sizeof(lf.FaceName));
strncpy_s(lf.FaceName, sizeof(lf.FaceName), fontName.c_str(), fontName.length() + 1);
}
error C2664: 'errno_t strncpy_s(char *,rsize_t,const char *,rsize_t)' : cannot convert parameter 1 from 'WCHAR [32]' to 'char *'
Regards
Chad
Author
Hmm this seem sto be compiling fine now but I am worried about overflow
int CreateFont(std::wstring& name)
{
D3DXFONT_DESC lf.
assert(fontName.length() < sizeof(lf.FaceName));
wcscpy_s(lf.FaceName, sizeof(lf.FaceName), fontName.c_str());
}
how would you suggest I check for them.
Regards
Chad
int CreateFont(std::wstring& name)
{
D3DXFONT_DESC lf.
assert(fontName.length() < sizeof(lf.FaceName));
wcscpy_s(lf.FaceName, sizeof(lf.FaceName), fontName.c_str());
}
how would you suggest I check for them.
Regards
Chad
Quote:Original post by chadsxe
error C2664: 'errno_t strncpy_s(char *,rsize_t,const char *,rsize_t)' : cannot convert parameter 1 from 'WCHAR [32]' to 'char *'
If you use wide strings, you need to use the wide string version of strncpy_s called wcsncpy_s.
That depends on where the string is coming from. If it's chosen by the user, definitely not.
Author
Quote:Original post by SiCrane
That depends on where the string is coming from. If it's chosen by the user, definitely not.
It is chosen by the user. What steps can I take to assure that the user is under or equal to or less then 31 characters.
Regards
Chad
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