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Adrian99420

Combine string

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Codeka    1239
There's boost::erase_all, like so:
std::string str = "4F 6E 67";
boost::erase_all(str, " ");
std::cout << str << std::endl;
If you don't use boost, then you'll probably just have to do it manually: copy characters to a new string one by one, skipping over the ones you don't want.

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Adrian99420    100
Thanks for the reply. I can't use the erase function. I am quite new in C++ programming, can someone show me how to pick the character manually and then combine it again? Thanks in advance.

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dmatter    4825
Quote:
Original post by Codeka
If you don't use boost, then you'll probably just have to do it manually
You can still be terse using the the standard library:

std::string a("4F 6E 67");
std::string b;
std::remove_copy(a.begin(), a.end(), std::back_inserter(b), ' ');
std::cout << b;


Not as nice to look at without Boost but still easier than writing it manually.

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Adrian99420    100
Thanks for the reply. I am doing it in tis way, but seems like it doesnt work.

int j(0);
CString hexNewOutput;
int DataLength = 0;

hexstrOutput="4F 6E 67";
DataLength = hexstrOutput.GetLength();
for ( int i = 0; i<DataLength; i++)
{
if (hexstrOutput[i]!=' ')
{
hexNewOutput[j] = hexstrOutput[i];
j++;
}
}

Any comment?

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dmatter    4825
Presumably the character indexing operator[] of CString doesn't resize the string? So doing this: hexNewOutput[j] when that string has as size of zero is a bad idea. You can probably use the += operator to append the character though.

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bitshifter    113
No OOP, but you get the idea...

#include <stdio.h>

void MunchCharacter(char *str, char ch)
{
char *head = str;
char *tail = str;

while(*head != '\0')
{
if(*head != ch)
{
*tail++ = *head;
}

head++;
}

*tail = *head; // aka (*tail = '\0')
}

int main(int argc, char **argv)
{
char str[] = "AB C D E F";
char ch = ' ';

printf("Input: [%s]\n",str);
MunchCharacter(str,ch);
printf("Output: [%s]\n",str);

system("pause");
return 0;
}




[Edited by - bitshifter on November 12, 2009 12:28:29 AM]

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DevFred    840
Quote:
Original post by Codeka
If you don't use boost, then you'll probably just have to do it manually

Nope. Just use the remove-erase-idiom.

#include <algorithm>
#include <iostream>
#include <string>

int main()
{
std::string s = "4F 6E 67";
std::cout << s << std::endl;
s.erase(std::remove(s.begin(), s.end(), ' '), s.end());
std::cout << s << std::endl;
}

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Evil Steve    2017
Quote:
Original post by Adrian99420
Thanks for the reply, so any suggestion?
Surely you can do this yourself from the various methods everyone has provided?

And why is this (And every other thread you've posted), so urgent?

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owl    376

char* str = "4F 6E 67", val[7];
val[0]=str[0];val[1]=str[1];val[2]=str[3];val[3]=str[4];val[4]=str[6];val[5]=str[7];val[6]=0;

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