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Combine string

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Hi, this is what i am doing: I got a hex string : "4F 6E 67" I wish to combine the string to make it without the spacing which is "4F6E67". How can I do that? Thanks in advance.

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There's boost::erase_all, like so:
std::string str = "4F 6E 67";
boost::erase_all(str, " ");
std::cout << str << std::endl;
If you don't use boost, then you'll probably just have to do it manually: copy characters to a new string one by one, skipping over the ones you don't want.

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Thanks for the reply. I can't use the erase function. I am quite new in C++ programming, can someone show me how to pick the character manually and then combine it again? Thanks in advance.

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Wait, is this related to your other post? If you didn't want spaces in the string to begin with, why are you using code that puts them there?

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Quote:
Original post by Codeka
If you don't use boost, then you'll probably just have to do it manually
You can still be terse using the the standard library:

std::string a("4F 6E 67");
std::string b;
std::remove_copy(a.begin(), a.end(), std::back_inserter(b), ' ');
std::cout << b;


Not as nice to look at without Boost but still easier than writing it manually.

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Thanks for the reply. I am doing it in tis way, but seems like it doesnt work.

int j(0);
CString hexNewOutput;
int DataLength = 0;

hexstrOutput="4F 6E 67";
DataLength = hexstrOutput.GetLength();
for ( int i = 0; i<DataLength; i++)
{
if (hexstrOutput!=' ')
{
hexNewOutput[j] = hexstrOutput;
j++;
}
}

Any comment?

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Presumably the character indexing operator[] of CString doesn't resize the string? So doing this: hexNewOutput[j] when that string has as size of zero is a bad idea. You can probably use the += operator to append the character though.

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Sorry, I think I edited my post while you were replying:
Quote:
Original post by dmatter
You can probably use the += operator to append the character though.
That's assuming your CString refers to the ATL/MFC CString class.

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No OOP, but you get the idea...

#include <stdio.h>

void MunchCharacter(char *str, char ch)
{
char *head = str;
char *tail = str;

while(*head != '\0')
{
if(*head != ch)
{
*tail++ = *head;
}

head++;
}

*tail = *head; // aka (*tail = '\0')
}

int main(int argc, char **argv)
{
char str[] = "AB C D E F";
char ch = ' ';

printf("Input: [%s]\n",str);
MunchCharacter(str,ch);
printf("Output: [%s]\n",str);

system("pause");
return 0;
}




[Edited by - bitshifter on November 12, 2009 12:28:29 AM]

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Quote:
Original post by Codeka
If you don't use boost, then you'll probably just have to do it manually

Nope. Just use the remove-erase-idiom.

#include <algorithm>
#include <iostream>
#include <string>

int main()
{
std::string s = "4F 6E 67";
std::cout << s << std::endl;
s.erase(std::remove(s.begin(), s.end(), ' '), s.end());
std::cout << s << std::endl;
}

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Quote:
Original post by Adrian99420
Thanks for the reply, so any suggestion?
Surely you can do this yourself from the various methods everyone has provided?

And why is this (And every other thread you've posted), so urgent?

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char* str = "4F 6E 67", val[7];
val[0]=str[0];val[1]=str[1];val[2]=str[3];val[3]=str[4];val[4]=str[6];val[5]=str[7];val[6]=0;

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Thanks for the advice guys, I did it using += operator to append the character. Juz rushing for a project, so can't put too much time on programming details. Thanks anyway.

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