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tm1rbrt

Is it possible to solve this?

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(I'm assuming the 100° triangle is isosceles - that the two shorter sides both have the same length, d.)

Then d = sqrt(252 + 302) / (2 * sin(50°)) = approx 25.49.

Note the side labeled 55 isn't actually 25 + 30 = 55 units in length.. it's sqrt(252 + 302), which is approximately 39.05.

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