can c-string's be created dynamicaly
Author
can I creat a c-string synamicaly since I dont know how much data will be entered.
Is there a way to let the user enter a bunch of data and the read the size to creat a c-string?
I'm guessing english isn't your first language as you're from germany.
Could you try explaining your problem/question a little more in depth? It could make perfect sense to others, but I'm a little confused on what you're actually asking for.
Could you try explaining your problem/question a little more in depth? It could make perfect sense to others, but I'm a little confused on what you're actually asking for.
Author
instead of
const int SIZE = 100;
char input[SIZE];
cout<<"Enter a string ";
cin.getline(input, SIZE);
I want the user to be able to input a string as long as they want then I creat the char to use it.
some thing like
char *input;
cin<< as much data as they want
input = new char(x.size)
const int SIZE = 100;
char input[SIZE];
cout<<"Enter a string ";
cin.getline(input, SIZE);
I want the user to be able to input a string as long as they want then I creat the char to use it.
some thing like
char *input;
cin<< as much data as they want
input = new char(x.size)
Author
Quote:Original post by phresnel
In C++?
I know I can use a string but I want to use a c-string
its easyer for me to minipulate a c-string then a string class
Quote:Original post by kingpinzsQuote:Original post by phresnel
In C++?
I know I can use a string but I want to use a c-string
its easyer for me to minipulate a c-string then a string class
So easy that your code is bugfull and dangerous, open to many kinds of malicious attacks. Something that nobody should install on his machine.
Just use string and be done:
#include <iostream>#include <string>int main () { std::string name; std::getline(std::cin, name);}For formatting strings, use stringstream:
#include <sstream>int main () { std::stringstream ss; ss << 42 << 0.5f << 0.5 << "hello world" << '\n'; std::cout << ss.str();}
Quote:I know I can use a string but I want to use a c-stringstd::string is most likely exactly what you are looking for.
its easyer for me to minipulate a c-string then a string class
Can you give an example of how C strings are easier to manipulate? Almost any string-related operation I can think of is simpler, safer, and takes fewer lines of code with string than with a raw character array.
(I'm not saying there's never a reason to prefer C-style strings, but 'easier to manipulate'? That seems a bit odd.)
You can use fgets(stdin, ...) and dynamically reallocate the array you're reading into until you've read all input.
Author
Quote:Original post by phresnelQuote:Original post by kingpinzsQuote:Original post by phresnel
In C++?
I know I can use a string but I want to use a c-string
its easyer for me to minipulate a c-string then a string class
So easy that your code is bugfull and dangerous, open to many kinds of malicious attacks. Something that nobody should install on his machine.
Just use string and be done:
}
First of all this is personal use and not to be used by any one else.
Its a consule app to learn how c++ works
Also in my c++ class in collage we had to do a full chapter on c-string and I was just wondering if they could be created dynamicaly
and third
char menu();int vowel_counter(char *);int consonants_counter(char *); void cls( HANDLE );int main(){ const int SIZE = 100; char input[SIZE]; char menu_input; cout<<"Enter a string "; cin.getline(input, SIZE); menu_input = menu(); while(toupper(menu_input) != 'E') { if(toupper(menu_input) == 'A') { cout<<"The number of vowels in your string is "<<vowel_counter(input)<<endl; cout<<"Press a key to continue"<<endl; cin.ignore(); cin.get(); } else if(toupper(menu_input) == 'B') { cout<<"the number of consonants in your string is "<<consonants_counter(input)<<endl; cout<<"Press a key to continue"<<endl; cin.ignore(); cin.get(); } else if(toupper(menu_input) == 'C') { cout<<"The count of both consonants and vowels is "<<vowel_counter(input) + consonants_counter(input)<<endl; cout<<"Press a key to continue"<<endl; cin.ignore(); cin.get(); } else if(toupper(menu_input) == 'D') { cout<<"Enter a string "; cin.ignore(); cin.getline(input, SIZE); } menu_input = menu(); } cout<<"Exiting the program "<<endl;system("PAUSE");return 1;}char menu(){ HANDLE hConsole; hConsole = GetStdHandle(STD_OUTPUT_HANDLE);cls(hConsole);char input; cout<<"\t\tCount Vowels, Consonants or Both."<<endl<<endl; cout<<"\t A) Count the number of vowels in the string"<<endl <<"\t B) Count the number of consonants in the string"<<endl <<"\t C) Count both the vowels and consonants int the string"<<endl <<"\t D) Enter another string"<<endl <<"\t E) Exit the program"<<endl<<endl <<"\t Enter a letter "; cin>>input;return input;}int vowel_counter(char *cString){ char vowles[5]={'A', 'E','I', 'O', 'U'}; int counter = 0; while(*cString != '\0') { for(int i = 0; i<5; i++) { if(toupper(*cString) == vowles) { counter++; } } cString++; }return counter;}int consonants_counter(char *cString){char consonants[21]={'B', 'C','D', 'F', 'G', 'H' ,'J','K','L','M','N','P','Q','R','S','T','V','W','X','Y','Z'}; int counter = 0; while(*cString != '\0') { for(int i = 0; i<21; i++) { if(toupper(*cString) == consonants) { counter++; } } cString++; }return counter;}This is how it is easyer to use
Quote:Original post by kingpinzs
Its a consule app to learn how c++ works
This is how C works, to which C++ is mostly compatible.
Quote:Also in my c++ class in collage we had to do a full chapter on c-string and I was just wondering if they could be created dynamicaly
If this is a 101 class, than they shouldn't be teaching raw string manipulation.
But if you really need it, you should at least use the "n" versions from <cstring>. And the only way for doing what you want (that is, reading in an arbitrary sized string, i.e. where a SIZE-constant is conceptually wrong) is char-wise reading, and keeping the input characters in a container, until '\n' is read.
Quote:and third
*** Source Snippet Removed ***
This is how it is easyer to use
No, that's not easier.
Also, programs shouldn't halt once they are finished, especially not through spawning a new process.
This topic is closed to new replies.
Advertisement
Popular Topics
Advertisement
