OK so i'm pretty sure this is right but before i write a whole bunch more i want to confirm. ok so i think this should give me a duplicate icosahedron that is half as big (well extends away from the middle half as far).
note: Asm is for Zenith angle and Theta is for Azimuth (i mixed Zenith and Azimuth of a bit)
vertices's to make icosahedron
const GLfloat P1[] = {0.0f, 1.0f, G_RATIO};
const GLfloat P2[] = {0.0f,-1.0f, G_RATIO};
const GLfloat P3[] = { 0.0f,-1.0f, -G_RATIO};
const GLfloat P4[] = {0.0f, 1.0f, -G_RATIO};
const GLfloat P5[] = {1.0f,G_RATIO, 0.0f};
const GLfloat P6[] = { -1.0f,G_RATIO, 0.0f};
const GLfloat P7[] = { -1.0f, -G_RATIO, 0.0f};
const GLfloat P8[] = {1.0f,-G_RATIO, 0.0f};
const GLfloat P9[] = { G_RATIO,0.0f, 1.0f};
const GLfloat P10[] = { -G_RATIO, 0.0f, 1.0f};
const GLfloat P11[] = {-G_RATIO,0.0f, - 1.0f};
const GLfloat P12[] = { G_RATIO,0.0f, -1.0f};
vertices's to fill
GLfloat P1[3];
GLfloat P2[3];
GLfloat P3[3];
GLfloat P4[3];
GLfloat P5[3];
GLfloat P6[3];
GLfloat P7[3];
GLfloat P8[3];
GLfloat P9[3];
GLfloat P10[3];
GLfloat P11[3];
GLfloat P12[3];
OK here is where my question is. if i repeat this process for all 12 vertices will i get what i want.
r = sqrt(pow(P1[0],2)+pow(P1[1],2)+ pow(P1[2],2));
theta = acos(((P1[2])/(sqrt(pow(P1[0],2)+pow(P1[1],2)+pow(P1[2],2)))));
Asm = atan2(P1[0],P1[1]);
r = r/2;
RP1[0] = r*sin(theta)*cos(Asm);
RP1[1] = r*sin(theta)*cos(Asm);
RP1[2] = r*cos(theta);
