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# Ignore. Didn't have all parts to the problem. fixed

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Ignore. Didn't have all parts to the problem. fixed

[Edited by - carlsonc on July 7, 2010 3:57:58 AM]

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Your test, "if n % 6 == 0 or n % 9 == 0 or n % 20 == 0" is completely wrong: it finds multiples of one McNugget offer, not linear combinations of all three.

I would iterate through a,b,c triples in order of increasing a+b+c=k, recording the corresponding n=6a+9b+20c values, and storing a set of the impossible n values.
Given the set of n values obtained for each k, you can then a) look for 6 consecutive integers among them (termination condition) and b) remove them from the set of n values that couldn't be obtained with a smaller k (result update).

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Figured out the huge problem...and why I was so confused. I was missing an important part of the problem and I figured it out now.

P.S.
Why wouldn't "if n % 6 == 0 or n % 9 == 0 or n % 20 == 0" get all possible answers for 6, 9, and 20 assuming the program incremented n. I didn't want them separated, It just needed to be divisible by either 6, 9, or 20.

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