Hey everyone, I'm trying to make a program where you enter what all you need to get from the grocery store. It then put's those items into a list, sorts the list than prints the list. This is the code I have as of right now..





def menu():
print "Welcome"
print "What would you like to do?"
print " "
print "1) Create"
print "2) Quit"
return input("Choose an option: ")

list = []

def add(raw_input):
list.append( (raw_input) )


loop = 1
choice = 0

while loop == 1:
choice = menu()
if choice == 1:
add(raw_input("Enter an item: "))
q = raw_input("Would you like to add another item? y/n: ")
if q == y:
add(raw_input("Enter an item: "))
if q == n:
loop = 0
elif choice == 2:
loop = 0
print "end"




When I run it, it runs normally, It allows me to enter my first item, and it puts it into the list, it than ask, "would you like to add another item? y/n

and if i hit either y or n it gives me this error..

Traceback (most recent call last):
File "C:\Python24\test1", line 23, in -toplevel-
if q == y:
NameError: name 'y' is not defined

I thought since i was using q = raw_input I figured it would work, i'm not too sure whats wrong. Can anyone help?

the problem in that comparison is that python is looking for a variable named y. You should instead use character 'y'. So:

q == 'y'
q == 'n'

Hey, thanks that helped a lot! is there anyway I can just loop that general area? because if I choose 'y' it will ask for another item, than I type the item in then it loops the whole entire code :\

Hello orbikk, I took the liberty of cleaning up your code.
Changes and explanations:

• Multiline strings. Look at the code.EDIT: ''' '''


• Don't forget to use raw_input for input.


• When you receive input(Trough raw_input) you get it as a string even if it is a number.


• You can use while as a conditional + loop. I am sure you will like that trick.:D


• The function add is only called once in your whole code. It is better to take it off.

Hope it helps :D