It really isn't difficult to write the algorithm for duplicating the vertex and normals and texcoords.
If you have a line like
f 1/3/4 5/5/5 2/4/3

that is a triangle.
First, we must subtract by 1 so we get
f 0/2/3 4/4/4 1/3/2

now, let's do it

j=0;
k=0;
m=0;
for(i=0; i<3; i++)
{
new_vertexarray[k]=vertexarray[vertex_index[j]*3]; //X
new_vertexarray[k+1]=vertexarray[vertex_index[j]*3+1]; //Y
new_vertexarray[k+2]=vertexarray[vertex_index[j]*3+2]; //Z

new_normalarray[k]=normalarray[normal_index[j]*3]; //NX
new_normalarray[k+1]=normalarray[normal_index[j]*3+1]; //NY
new_normalarray[k+2]=normalarray[normal_index[j]*3+2]; //NZ

new_texcoordarray[m]=texcoordarray[tex_index[j]*2]; //S
new_texcoordarray[m+1]=texcoordarray[tex_index[j]*2+1]; //T
k+=3;
m+=2;
j++;
}


in the end, new_vertexarray would have to be of size 9 (3 vertex)
in the end, new_normalarray would have to be of size 9 (3 vertex)
in the end, new_texcoordarray would have to be of size 6 (3 vertex)

You also need a new_indexarray.
Needs to be size 3.
The values will start from 0 and go up.

I suggest you to think and write whatever algorithm you want. If you are not good with algorithms, forget about programming.

Quote:Original post by V-man
...

Nice, but there are shared vertices anyway, so I don't think duplicating every vertex is a good idea.