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method pointer

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Guest Anonymous Poster
Yes, there is.

i.e., void (ClassName::*func)(int i);

You have to invoke it with an object though, you can''t just call it like a regular function pointer.

Here''s a full example:

  
#include <iostream.h>

class A
{
public:
void f() { cout << "In f...\n"; }
};

void (A::*func)();

void main()
{
A *a = new A;
func = a->f;
(a->*func)();
delete a;
}

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