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# moving 2d array to 3d array

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if i have an array of floats how can i turn that array into a multidimensional array. ex: [color="#8b0000"]sector[9] = {1,2,3,4,5,6,7,8,9} what i want is to change "sector" into "sector2"......[color="#8b0000"]sector2[3][3]={{1,2,3},{4,5,6},{7,8,9}};

So if you under stand the function required and logic an explanation would be awesome.[color="#8b0000"]

[color="#000000"]Im using c++

thanks

Green

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You will need two identifiers. Then, the simplest, lowest-level solution is to just use [font="'Courier New"]memcpy [/font]and take advantage of C definition of arrays. This will possibly wreak havoc when dealing with arrays of objects.
A more C++ solution would be to have two loops on row and column respectively... try sketching it first.

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if i have an array of floats how can i turn that array into a multidimensional array. ex: [color="#8b0000"]sector[9] = {1,2,3,4,5,6,7,8,9} what i want is to change "sector" into "sector2"......[color="#8b0000"]sector2[3][3]={{1,2,3},{4,5,6},{7,8,9}};

So if you under stand the function required and logic an explanation would be awesome.[color="#8b0000"]

[color="#000000"]Im using c++

thanks

Green

It sounds like you want to just put the information from one array into another array, correct?

If so this sounds like you just need a nested loop to solve your re-locating problem.

 int first=3; int second = 3; int sector[9] = {1,2,3,4,5,6,7,8,9}; int sector2[first][second]; for(int i = 0, s_count = 0; i<first; i++) for(int j = 0; j<second; j++, s_count++) //update s_count here so that it can update as the j position updates. sector2[j] = sector[s_count]; for(int i = 0, s_count = 0; i<first; i++) //this is for displaying the results and not part of the transfer process for(int j = 0; j<second; j++) cout<<sector2[j]; 

In this code s_count is kept track of so that you can add to each new array section first run through it starts at 0, the second at 3, third at 6...etc

EDIT:

I suggest doing as Krohm suggested, sketch this out, it'll give you a better understanding than someone just explaining it to you would. Edited by IggyT

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Hey thanks, that's exactly what i am looking for thanks

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