[color="#1C2837"]I don't think you'd want to intersect the circles themselves, imagine you were looking straight on so that one of the circles was completely perpendicular to the screen making it impossible to reliably select it with mouse (corresponding to say spinning it around) that'd be a bit counter-intuitive
You could just subtract the centre of the object from the intersection point, and project onto each circle axis to choose the nearest i guess.
public bool TestRayAgainst(CollisionDetection.Ray ray, ref Contact3D contact)
{
int index = -1;
Contact3D c = new Contact3D();
if (TestStaticRaySphere(ray, boundingSphere, ref c))
{
contact.isColliding = c.isColliding;
contact.isIntersecting = c.isIntersecting;
contact.nEnter = c.nEnter;
contact.nExit = c.nExit;
contact.objects = c.objects;
contact.penetration = c.penetration;
contact.point = c.point;
contact.tEnter = c.tEnter;
contact.tExit = c.tExit;
// Subtract the sphere centre from the intersection point
Vector3 p = c.point - boundingSphere.Position;
index = MathTools.Max3Index(
Math.Abs(Vector3.Dot(p, Vector3.UnitX)), // 0
Math.Abs(Vector3.Dot(p, Vector3.UnitY)), // 1
Math.Abs(Vector3.Dot(p, Vector3.UnitZ)) // 2
);
}
switch (index)
{
case -1:
{
SetGrabStateNone();
return false;
}
case 0:
{
SetGrabStateX();
return true;
}
case 1:
{
SetGrabStateY();
return true;
}
case 2:
{
SetGrabStateZ();
return true;
}
default:
return false;
}
}
[color=#1C2837][size=2]Well you should be choosing the minimum projection ;)
[color=#1C2837][size=2][/quote]
[color="#1c2837"]
[color=#1C2837][size=2][color=#000000] index [color=#666600]=[color=#000000] [color=#660066]MathTools[color=#666600].[color=#660066]Min3Index[color=#666600]([color=#000000]
[color=#660066]Math[color=#666600].[color=#660066]Abs[color=#666600]([color=#660066]Vector3[color=#666600].[color=#660066]Dot[color=#666600]([color=#000000]p[color=#666600],[color=#000000] [color=#660066]Vector3[color=#666600].[color=#660066]UnitX[color=#666600])),[color=#000000] [color=#880000]// 0[color=#000000]
[color=#660066]Math[color=#666600].[color=#660066]Abs[color=#666600]([color=#660066]Vector3[color=#666600].[color=#660066]Dot[color=#666600]([color=#000000]p[color=#666600],[color=#000000] [color=#660066]Vector3[color=#666600].[color=#660066]UnitY[color=#666600])),[color=#000000] [color=#880000]// 1[color=#000000]
[color=#660066]Math[color=#666600].[color=#660066]Abs[color=#666600]([color=#660066]Vector3[color=#666600].[color=#660066]Dot[color=#666600]([color=#000000]p[color=#666600],[color=#000000] [color=#660066]Vector3[color=#666600].[color=#660066]UnitZ[color=#666600]))[color=#000000] [color=#880000]// 2[color=#000000]
[color=#666600]);
[color=#1C2837][size=2]
[color="#1c2837"]That works better, thank you.
[color="#1c2837"]
[color="#1c2837"]There are still situations where the incorrect axis is chosen:
[color="#1c2837"]
[color="#1c2837"]
[color="#1c2837"]
[color="#1c2837"]The mouse is clicking on the blue ring (normal = (0,0,1) but the red ring is selected (normal = (1, 0, 0).
[color="#1c2837"]
[color="#1c2837"]What might be going on here?
[color="#1c2837"]
[color="#1c2837"]The mouse is clicking on the blue ring (normal = (0,0,1) but the red ring is selected (normal = (1, 0, 0).
[color="#1c2837"]What might be going on here?
you might be clicking the blue ring, but the intersection with the sphere which you test is closer to the other, which also seems clear from your picture.
--edit: perhaps you should instead be looking for the closest circle based on their 2d projections instead?
This would be equivalent to finding the distance from the point to the border of each ellipse; or in 3d, the distance between the unprojected mouse coordinate ray, to each circle
What is the coordinate for the point, and the value of each projection?
[/quote]
Point = {X:-1.884914 Y:3.893975 Z:8.819122}
Sphere Position = {X:-1.1665 Y:2.148515 Z:7.9195}
Point - Sphere Position = {X:-0.7184134 Y:1.74546 Z:0.899622}
Projection onto X axis (Absolute value) = 0.718413353
Projection onto Y axis (Absolute value) = 1.74545956
Projection onto Z axis (Absolute value) = 0.899621964
