# deriving

This topic is 2448 days old which is more than the 365 day threshold we allow for new replies. Please post a new topic.

## Recommended Posts

Guys,

those values down are rotation values, the frames= time. Is it possible to determine (or is there any technique) how the animation would continue? It is a bouncing ball.
 Transform Rotation Frame degrees 0 0.976754 1 3.24782 2 6.76221 3 11.4515 4 17.2204 5 23.9403 6 31.4499 7 39.5613 8 41.1397 9 37.4979 10 34.7966 11 32.8202 12 31.5264 13 30.923 14 31.0173 15 31.8037 16 33.2615 17 35.3535 18 38.0259 19 41.2095 20 41.3825 21 40.0203 22 39.3244 23 39.1892 24 39.5702 

##### Share on other sites

Guys,

those values down are rotation values, the frames= time. Is it possible to determine (or is there any technique) how the animation would continue? It is a bouncing ball.
 Transform Rotation Frame degrees 0 0.976754 1 3.24782 2 6.76221 3 11.4515 4 17.2204 5 23.9403 6 31.4499 7 39.5613 8 41.1397 9 37.4979 10 34.7966 11 32.8202 12 31.5264 13 30.923 14 31.0173 15 31.8037 16 33.2615 17 35.3535 18 38.0259 19 41.2095 20 41.3825 21 40.0203 22 39.3244 23 39.1892 24 39.5702 

Guessing what comes next is more art than science. What you are looking for is called extrapolation in numerical analysis. Basically, you have a set of (x,y) pairs and you want to know what happens outside of the domain. Try reading up on the topic in a numerical methods book or at a website then try implementing some of the many methods available and pick the one that gives the best result. Any numerical methods book will certainly have a chapter on this topic.

http://www.developer...ings-Part-1.htm

##### Share on other sites
If you plot the points, you'll see that they seem to follow three parabolas, which correspond to free-falling trajectories between bounces. You can select the points that clearly belong to one of the parabolas and fit the three coefficients that define a parabola for each of the three parabolas. You can then see how much lower the second bounce was than the first one, and from there deduce the elasticity of the collision. Or you can simply assume that the energy loss is such that the height of the successive bounces follows a geometric progression. That would allow you to extrapolate the position going forward.

##### Share on other sites
jesse7, alvaro thank you very much!

i will read the extropolation chapter and look at the methods! Thank you alvaro for the explanation, seems logical, will give it a try too.

bye

1. 1
Rutin
24
2. 2
3. 3
JoeJ
18
4. 4
5. 5
gaxio
11

• 38
• 23
• 13
• 13
• 17
• ### Forum Statistics

• Total Topics
631708
• Total Posts
3001837
×