Jump to content
  • Advertisement
Sign in to follow this  
nuclear123

overloaded operator[]

This topic is 2531 days old which is more than the 365 day threshold we allow for new replies. Please post a new topic.

If you intended to correct an error in the post then please contact us.

Recommended Posts

the tutorial i am currently reading states the following


class IntList
{
private:
int m_anList[10];

public:
void SetItem(int nIndex, int nData) { m_anList[nIndex] = nData; }
int GetItem(int nIndex) { return m_anList[nIndex]; }
};


The subscript operator is one of the operators that must be overloaded as a member function[/quote]
Why "must" it be a member function? i dont see a problem with making it a friend and doing the following.


class IntList
{
private:
int m_anList[10];

public:
void SetItem(int nIndex, int nData) { m_anList[nIndex] = nData; }
int GetItem(int nIndex) { return m_anList[nIndex]; }
friend operator[]( IntList& this, int index );
};


IntList& operator[]( IntList& this, int nindex )
{
return m_anList[nIndex];
}


what does it mean it "must" be a member function? will this give a compiler error? or is it reffering to something else im missing? -thanks ( i would put in a compiler but the PC i'm using is not mine )

Share this post


Link to post
Share on other sites
Advertisement
To summarize, if [font="Courier New"]operator[] [/font]was allowed as a namespace-level function instead of a member function, usage would appear like [font="Courier New"]intList [] 3[/font] instead of [font="Courier New"]intList[3][/font].

Share this post


Link to post
Share on other sites
Sign in to follow this  

  • Advertisement
×

Important Information

By using GameDev.net, you agree to our community Guidelines, Terms of Use, and Privacy Policy.

We are the game development community.

Whether you are an indie, hobbyist, AAA developer, or just trying to learn, GameDev.net is the place for you to learn, share, and connect with the games industry. Learn more About Us or sign up!

Sign me up!