Switch statement problem. (C++)

Eric Kalantyrski · 2012-02-19T00:36:13

When I use the switch statement, and after I made the first case, I decided to try out if it would work but when entering the letter E beacause that is the only case which exists I dont get anything after press E than enter. Can someone explain. #include <iostream> #include <cstdlib> #include <ctime> using namespace std; int main() { int dif; srand(time(0)); cout << "Please Select a Difficllty E = Easy M = Medium H = Hard" <<endl; cin >> dif; int gn; switch(dif){ case 'e || E': int number = 1+(rand()%10); cout << "Guess a number beetween 1 and 10" <<endl; cin >> gn; if(gn == number){ cout << "You won!" <<endl; } break; } } Thanks.

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Started by Kalner February 18, 2012 11:52 PM

14 comments, last by Kalner 12 years, 2 months ago

Alpha_ProgDes

6,963

February 19, 2012 12:12 AM

Part of the reason you're not getting any results is that you're "choice" is an integer, use a char when you want a char.

Wouldn't 'E' or 'e' just be converted to its ASCII number equivalent automatically in this situation?

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SiCrane

11,840

February 19, 2012 12:14 AM

No, it would set the fail bit on the stream.

Alpha_ProgDes

6,963

February 19, 2012 12:15 AM

Oh.

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TheUnbeliever

963

February 19, 2012 12:17 AM

Also, (and this has nothing to do with your problem but still should be done) where in the world is your return 0;?

There's an exemption for main. (It implicitly returns 0 unless otherwise specified.)

[TheUnbeliever]

Alpha_ProgDes

6,963

February 19, 2012 12:23 AM

[quote name='Alpha_ProgDes' timestamp='1329610210' post='4914359']Also, (and this has nothing to do with your problem but still should be done) where in the world is your return 0;?

There's an exemption for main. (It implicitly returns 0 unless otherwise specified.)
[/quote]
I know, but still.... it's just wrong not to have it.

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