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Light Probability Distribution - Extra Cos Theta term

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Hi,

According to [url="http://graphics.stanford.edu/courses/cs348b-03/papers/veach-chapter10.pdf"]http://graphics.stan...h-chapter10.pdf[/url] , the pdf for choosing a point

PA(yi) = P(projected solid angle) * G
= P(surface area) * conversion to projected solid angle * G
= P(surface area) * (t^2 / (cos(wi) * cos(wo))) * ((cos(wi) * cos(wo)) / t^2)
= P(surface area)

In my case, P(surface area) is (1/(A * 2 * PI)) since I'm unifomely sampling a hemisphere with respect to solid angle.

However, the correct term is P(surface area) * (1/cos(wo)).

I think I'm missing some important concept here. Does anyone familiar with this know what I'm doing wrong? Edited by jameszhao00

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This topic is 2051 days old which is more than the 365 day threshold we allow for new replies. Please post a new topic.

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