I'm not real good at math so I'm wondering if someone here could help me.
How would I reverse this?:
a = (last a * b / constant) + constant;
Thanks
Reversing an equation
Reverse it for what? last, or b?
You just go:
[s]a = (last a * b / constant) + constant
a - constant = last * a * b / constant
(a - constant) * constant = last * a * b
((a - constant) * constant) / a = last * b
At this point you either divide both sides by last or b, depending on what you wish to solve for.[/s]
*scratch that I misread*
You just go:
[s]a = (last a * b / constant) + constant
a - constant = last * a * b / constant
(a - constant) * constant = last * a * b
((a - constant) * constant) / a = last * b
At this point you either divide both sides by last or b, depending on what you wish to solve for.[/s]
*scratch that I misread*
Oh my bad I misread it. Then you get:
a = (last a * b / constant) + constant;
a - constant = last a * b / constant
(a - constant) * constant = last a * b
last a = ((a - constant) * constant) / b
a = (last a * b / constant) + constant;
a - constant = last a * b / constant
(a - constant) * constant = last a * b
last a = ((a - constant) * constant) / b
Here's a pretty good tutorial on how to get to those solutions:
http://www.khanacademy.org/math/algebra/solving-linear-equations/v/rearrange-formulas-to-isolate-specific-variables
http://www.khanacademy.org/math/algebra/solving-linear-equations/v/rearrange-formulas-to-isolate-specific-variables
No joke... you should snag an Algebra for Dummies book. It's such a very useful thing to know! There are also AP study guides for algebra, which may be a little more in-depth. I usually bought my math books at the used book store. $5 for a $30 book. That way I get to have multiple pre-owned references for the price of one new reference! Cheap, effective.
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