# how to draw threat dome

This topic is 2218 days old which is more than the 365 day threshold we allow for new replies. Please post a new topic.

## Recommended Posts

[color=#000000][font=verdana, arial, helvetica][size=2]

Hi

[/font]

[color=#000000][font=verdana, arial, helvetica][size=2]

I want to implement a threat dome.

[/font][color=#000000][font=verdana, arial, helvetica][size=2]

So I am hoping some one could help me on this.

[/font]

[color=#000000][font=verdana, arial, helvetica][size=2]

[/font]

##### Share on other sites

[color=#000000][font=verdana, arial, helvetica][size=2]I want to implement a threat dome.[/font]

[color=#000000][font=verdana, arial, helvetica][size=2]So I am hoping some one could help me on this.[/font]

Please explain what a threat dome is, and what your requirements on functionality are.

##### Share on other sites
A9876 Edited by A9876

##### Share on other sites
Threat Dome displays the volume that is visible from a given point on the terrain. Threat Dome looks like top half of a sphere that accurately displays the areas viewable from the defined point. Any point inside the [color=#FFFFFF][background=#0a246a]threat dome[/background] can be viewed from the dome’s pivot point.

I think this is what is called frustum then?

If you use OpenGL, the projection matrix will compute it for you.

##### Share on other sites
A9876 Edited by A9876

##### Share on other sites
If I understand correctly what you want, this is all but trivial.

You basically want to construct a dome from the visible horizon from some arbitrary point. This is easy if you know the horizon (just extrude towards +Z and scale, repeat a few times, and there's your dome), but finding the horizon line is not easy.

Assuming a heightmap terrain (you didn't specify, but otherwise it is still a lot harder!) this means you have to ray-march over the terrain heightmap up to a maximum viewing distance and ignore everything that is less than your maximum value (because something that is below a higher elevation won't be visible). So basically, you only ever care about values that are higher than any ones (including the point you're standing on) you've seen before. Anything less isn't visible as long as the terrain isn't transparent and doesn't have holes. Eventually you will have reached a maximum distance (either practical because it's no longer of interest, or for effects like atmospheric attenuation, earth curvature, etc.).

Do that for, say, a dozen cardinal directions. This is a very coarse approximation. If the terrain between two rays is sufficiently "similar", your estimate is good, the distance that you find on two sibling rays is identical or more or less the same. If it is not, then your estimate is not accurate, so shoot another ray at the half angle between the two, repeating this recursively until you are happy with the accuracy. Edited by samoth

##### Share on other sites

If I understand correctly what you want, this is all but trivial.

You basically want to construct a dome from the visible horizon from some arbitrary point. This is easy if you know the horizon (just extrude towards +Z and scale, repeat a few times, and there's your dome), but finding the horizon line is not easy.

Assuming a heightmap terrain (you didn't specify, but otherwise it is still a lot harder!) this means you have to ray-march over the terrain heightmap up to a maximum viewing distance and ignore everything that is less than your maximum value (because something that is below a higher elevation won't be visible). So basically, you only ever care about values that are higher than any ones (including the point you're standing on) you've seen before. Anything less isn't visible as long as the terrain isn't transparent and doesn't have holes. Eventually you will have reached a maximum distance (either practical because it's no longer of interest, or for effects like atmospheric attenuation, earth curvature, etc.).

Do that for, say, a dozen cardinal directions. This is a very coarse approximation. If the terrain between two rays is sufficiently "similar", your estimate is good, the distance that you find on two sibling rays is identical or more or less the same. If it is not, then your estimate is not accurate, so shoot another ray at the half angle between the two, repeating this recursively until you are happy with the accuracy.

Thank You...

1. 1
Rutin
21
2. 2
3. 3
JoeJ
16
4. 4
5. 5

• 26
• 20
• 13
• 13
• 17
• ### Forum Statistics

• Total Topics
631700
• Total Posts
3001781
×