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LC-3 Assembly problem

3 posts in this topic

So I am trying to create a game in assembly just for fun.

[color=#FF0000][b]EDIT: Please read my second post, it simplifies my question a lot.[/b][/color]

In the game you have an inventory and some items. Must the game is actually finished already, and each subroutine works. However, I am having problems printing to the screen.

I have printed to the screen before but it was a pain.

I’m trying to create a function (subroutine) to display the binary content of R0 to the console. So I want it to print 1 or 0 for each bit; which will mean something in the game. I start in R0[15]…R0[0] end there.

;AND R3, R3, #0

AND R0, R0, R3
CHECK ADD R0, R0, #1
TRAP x21
ELSE AND R0, R0, #0
TRAP x21
MASK .FILL x8000 ; Mask x8000

There has to be an easy way to do this. Please help. Edited by Cuajin

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I haven't done assembly since the Z80 and 486, so I can't be of much help. But kudos to your craziness. I recall the run of machine crashes I had just making a Paint-like app in assembly.

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I think I found a big problem. I can print now, but not 0s.

[CODE].ORIG x3000

LD R2, data5 ; Load the ASCII code
AND R0, R2, #0
TRAP x21

data5 .FILL x0030 ; ASCII code x30[/CODE]

I can use the same code and print a 1, or any number, but 0 (zero) just does not print.

For sure R0 = 0

R2 = ASCII code x0030

My output looks like this: 111111

It should look like: 1011011

It is actually 2 bits shorter which means that the 0s are being ignored.

Please help Edited by Cuajin

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Is it that you're using AND instead of add? It's hard for me to read because I haven't worked with it before, but I think that (or something like that) is resulting in a character 0 instead of a character 48, and character 0 is non-printable.

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