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I need them helps... again!

For Beginners

Started by Kripis July 26, 2012 05:42 AM

2 comments, last by FredOrJoeBloggs 11 years, 8 months ago

Kripis

132

Author

July 26, 2012 05:42 AM

#include <iostream>

using namespace std;

int main()

{

    char a;

    char b = "y";

    char c = "n";



    cout << "Am I a troll? (n/y)";

    cin >> a;

    if(a == b){

	    cout << "?????????????????????????????" << endl;

	    cout << "???????????????????????????????" << endl;

	    cout << "???????????????????????????????" << endl;

	    cout << "???????????????????????????????" << endl;

	    cout << "???????????????????????????????" << endl;

	    cout << "???????????????????????????????" << endl;

	    cout << "???????????????????????????????" << endl;

	    cout << "???????????????????????????????" << endl;

	    cout << "???????????????????????????????" << endl;

	    cout << "???????????????????????????????" << endl;

	    cout << "???????????????????????????????" << endl;

	    cout << "???????????????????????????????" << endl;

	    cout << "???????????????????????????????" << endl;

	    cout << "???????????????????????????????" << endl;

	    cout << "???????????????????????????????";

    }

    if(a == c){

	    cout << "D'aw";

    }else{

	    cout << "Am I a troll? (n/y)";

	    cin >> a;

    }



    return 0;

}

I need help, what this program is meant to do is to ask if I'am a troll and if the answer == "y" then it will print out the ASCII troll face(

) and if the answer == "n" then it will print "D'aw" and if answer is anything else then it will ask again (I'm 99% sure that the else par I made is completly wrong so yeah, I'am a newbie in C++) BUT I get an error in line 8 and 9 or the lines with "char b = 'y' " and "char c = 'n' " it says "invalid conversion from 'const char*' to 'char'"

Krohm

5,051

July 26, 2012 05:59 AM

You confused strings with characters. They are not the same thing.



char b = "y"; // put addres of first element of array{'y', 0} in variable b. b is not a pointer thus invalid assignment.

char c = "n"; // same 



char d = 'y'; // correct

As a side note, you can compare char literals directly inside if conditional evaluations. char is not magic, it's 8 bit storage which, when fetched to cout is used to look up a glyph to display. What the quoting does is to tell the compiler to look inside for a char/escape sequence and encode it as appropriate storage.
Similarly, double-quoting informs the compiler to build a string.
They are two very different things. Be careful in particular that you cannot trivially compare raw c-strings (usage of [font=courier new,courier,monospace]std::string[/font] is encouraged).

Previously "Krohm"

Kripis

132

Author

July 26, 2012 06:03 AM