I tried searching for this for a bit but everything seemed a little advanced for me. I have a function pointer:

void (*fun)();

Then I have class.

class info
{
public:
    void think();
};

extern class info player;

Is there a way to point fun to the think function?

I tried

fun=player.think;

but that got me

error C3867: 'info::think': function call missing argument list; use '&info::think' to create a pointer to member

I'm sure it's either something simple or that the two functions are just incompatible. Could anyone please tell me what I'm missing?

Thanks for any help!

Member function pointers are fundamentally different from function pointers. Primarily because a member functions needs an object to be called. Search for member function pointers for a more in-depth explanation though, but the basic usage is as follows:

// define a member function pointer
void (info::*fptr)() = nullptr;
 
// assign the member function pointer to some member function
fptr = &info::think;
 
// call the member function on the player object
(player.*fptr)();

Ah, that makes complete sense. Thank you.

I tried searching for this for a bit but everything seemed a little advanced for me. I have a function pointer:

void (*fun)();

Then I have class.

class info
{
public:
    void think();
};

extern class info player;

Is there a way to point fun to the think function?

I tried

fun=player.think;

but that got me

error C3867: 'info::think': function call missing argument list; use '&info::think' to create a pointer to member

I'm sure it's either something simple or that the two functions are just incompatible. Could anyone please tell me what I'm missing?

Thanks for any help!

If you are interested in the details behind pointers-to-member-functions, and how you can build an efficient delegate solution, I'd like to refer you to my blog post about exactly that: http://molecularmusings.wordpress.com/2011/09/19/generic-type-safe-delegates-and-events-in-c/

Hope that helps!