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Can you overload the assignment operator to take multiple values? [FIXED]

3 posts in this topic

This is something I've been curious about. Say with certain structs/classes, you can define them while declaring them by assigning them to multiple values contained within curly braces. For instance, with the COORD struct:


COORD position = {0, 0, 0};


How do you do this in code? Or is this some strange special case? I can't find anything on the subject.


EDIT: I really should code before I speak. I'm pretty sure you can just define all the variables once you declare a struct, and it'll go down the list of the struct's variables, so if I were to have a similar struct, let's say Vector, with X, Y, and Z values, you would be able to declare and define a variable of its type with Vector = {0,0,0}; This doesn't work for assignment though, for some reason. Is there a way to do that?

Edited by StoneMask

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Semi-relevantly, here's a function I use in my code base for formatting strings.

	Creates a string from 'str', with every occurance of "%n" replaced with the nth argument.
	Example: String::Format("The time is now %1 on the %3 of %2", {time, month, day})
std::string Format(std::string text, const StringList &arguments)
	StringList symbols = {"%1", "%2", "%3", "%4", "%5", "%6", "%7", "%8", "%9", "%10", "%11", "%12", "%13", "%14", "%15"};
	unsigned int i = 0;
	for(const auto &arg : arguments)
		if(i <= symbols.size())
			text = String::ReplaceAll(text, symbols[i], arg);
	return text;

It takes advantage of C++11's curly-bracket "uniform initialization syntax" to initialize a std::vector<std::string> (typedef'd to StringList since I use them so frequently).

Just a quick and sloppy implementation that works fairly well. It could be optimized further (it's very Schlemiel at the moment), but I haven't needed to yet.


But yes, uniform initialization syntax works for other types:

#include <iostream>
struct Point
     int x = 0; //default value of 0
     int y = 0;
int main()
     Point point = {640, 480};
     std::cout << point.x << ", " << point.y << std::endl;
     return 0;


Try the code


It works, for example, in C++11's new tuple types. C++11 must be enabled on your compiler for you to have access to the new features. How you enable it varies from compiler to compiler, but for GCC/MinGW you pass in -std=c++11 (or -std=c++0x for older versions of GCC).


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