Is it possible to lerp between functions ?
The general formula that can be used for lerp between vectors is (1-t)v + tv1. But what if instead of a vector we put in a function like (1-t)x + v*x^2 where f(x) = x is the first function and g(x) = x^2 is second one. Will this work ?
Yes that would just be pointwise lerp between the functions evaluated at a specific point. A function can often be considered to be a vector anyway (e.g. the vector space C[0,1] is the space of all continuous functions defined in the interval [0,1]).
I am not sure if this is right but if we take some other functions that are not linear like quadratic, will this still than hold ?
Will the space than again be affine ?
Quadratic in t? As long as all you are doing is taking a weighted sum of things with weights that add up to one, you are in good shape with any affine space.
No, no. Nobody is restricting the discussion to only linear functions. The "linear" in "linear interpolation" (what "LERP" stands for) refers to the dependence on t.
I am a little confused. But anyway I can take any function I want for f(x) and g(x) so that (1-t)f(x) + tg(x) ?
What would be the cases where I could not take any function ?
But anyway I can take any function I want for f(x) and g(x) so that (1-t)f(x) + tg(x) ?
Yes.
What would be the cases where I could not take any function ?
I don't understand that question. If you are asking about situations where it is not OK to take linear combinations like that, think of two points on the surface of a doughnut, two 3D rotations or even two points on a circle. There might be ways to make something that behaves similarly to LERP in those cases, but it will be much less straight forward than (1-t)*A+t*B.
I don't understand that question. If you are asking about situations where it is not OK to take linear combinations like that, think of two points on the surface of a doughnut, two 3D rotations or even two points on a circle. There might be ways to make something that behaves similarly to LERP in those cases, but it will be much less straight forward than (1-t)*A+t*B.
I was asking that to see if there were cases where I could not do this.
Thank you, it is much clearer to me now.
