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Cryusaki

C++ Functions run when I don't want them to

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I want to make a function in main that will not run however just making the function causes it to run

I tried prototyping the function but I am using object that are made and in main and that is out of scope
That goes the same for above main, as the variables/objects inside were defined in main
How do I stop the program from running the function without calling it when I create it?

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My program has SFML so I am not going to post that code but here is simple version of what I mean

#include <iostream>

using namespace std;

int main()
{
    void function();
    {
        cout << "Hello world!" << endl;
    }

    return 0;
}

The program will say Hello World

but I want it to only run when i call the function later on

How do I stop that?

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My program has SFML so I am not going to post that code but here is simple version of what I mean

#include <iostream>

using namespace std;

int main()
{
    void function();
    {
        cout << "Hello world!" << endl;
    }

    return 0;
}

The program will say Hello World
but I want it to only run when i call the function later on
How do I stop that?

 

I see the problem, as previously noted by Paradigm Shifter and Washu, you're not coding a "function inside main".
What you are doing is declaring a function:
 

void function(); // Notice that ";", it marks the end of the function declaration

 
 
and then adding "Hello World!" to cout.

{
    cout << "Hello World!" << endl;
}

the { and } are just block separators, that you can use to limit scopes, between some other things.
So the function and the { cout } aren't related by any means.

Edited by dejaime

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I see my issue now, I haven't coded in a long time but I can't believe I made such a basic mistake

Thanks everyone but I have a new issue related to my original issue

How do I make a function that can work with a variable declared in the main?

#include <iostream>

using namespace std;

void function();

int main()
{
    int x = 5;

    return 0;
}

void function()
{
        cout << x << endl;
}

I get an error at second last line saying x is out of scope, I understand why I just don't know how to solve this

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