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Prune

Can a bindless_sampler be mapped as normal UBO instead of using glProgramUniformHandleui64vARB ?

4 posts in this topic

ARB_bindless_texture specifies functions like glProgramUniformHandleui64vARB to update an array of texture handles. Can one, instead, use a regular uniform buffer object of GLuint64 and map it and write the handles to it, as one would write elements to any other mapped buffer object?

Edited by Prune
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Given that UBOs use a "binding" index instead of "location", do I need to switch "location" to "binding" in my GLSL declaration to use a UBO for texture handles?

layout(location = SAMPLERS, bindless_sampler) uniform sampler2D textures[MAX_TEX];

-->

layout(binding = SAMPLERS, bindless_sampler) uniform sampler2D textures[MAX_TEX];

The reason I'm not sure is because ARB_bindless_texture says:

 

With GLSL 4.20, sampler and image uniforms may be initialized in the shader using

    layout(binding = integer-constant)

as described in section 4.4.4 "Opaque-Uniform Layout Qualifiers". When ARB_bindless_texture is supported, these initial binding values are always taken to mean a texture image or image unit number, not a bindless handle.

If this "binding" refers to an image unit, is it not different than the "binding" index of UBOs?

Edited by Prune
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The bindless_sampler qualifier is necessary for uniform samplers in the default block only. If you are going to use a UBO, then it would probably look something like this:

layout(binding = SAMPLERS, std140) uniform sampler_buffer
{
    sampler2D textures[MAX_TEX];
};

Binding points for bound textures and UBO/SSBOs are completely separate.

 

Edit: Fix'd

Edited by Chris_F
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Thanks. I actually feel dumb to have asked that since I was already using block like this for transforms.

 

Just a note that std430 can't be used for UBO as in your example, only SSBO.

Edited by Prune
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