Hi,
say i have the integer 12345, how do get the sum of each digit added together? IE: 1+2+3+4+5 = sum.
What i''ve done so far is converted the integer (12345) into a string, but now I''m not sure what to do next.
I''m doing this in Java,
Thanks,
Scott
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"If you try and don''t succeed, destroy all evidence that you tried."
converted to string from int, now add each character (number)
you could try
int sum_it(char* str,int nVals)
{
int tot=0;
for(int i=0;i {
tot+=(int)str;
}
tot-=nVals*((int)''0'');
return tot;
}
int sum_it(char* str,int nVals)
{
int tot=0;
for(int i=0;i {
tot+=(int)str;
}
tot-=nVals*((int)''0'');
return tot;
}
Try this.. it''s C code but i''m sure you can convert it. 
int x=123456;
int i=1;
int sum=0;
int n;
do
{
n=(x%(i*10))/i;
sum+=n;
i*=10;
}while(n);
Now sum equals 21.
int x=123456;
int i=1;
int sum=0;
int n;
do
{
n=(x%(i*10))/i;
sum+=n;
i*=10;
}while(n);
Now sum equals 21.
This isn''t the code I posted - taggs missing so here is an explanation instead
1= (int)(''1''-''0'')
2= (int)(''2''-''0'')
etc...
nuf said ?
1= (int)(''1''-''0'')
2= (int)(''2''-''0'')
etc...
nuf said ?
You don''t need to convert to string:
I wanna work for Microsoft!
int i = 123456; // integerint s = 0; // sumwhile(i){ s += (i % 10); i /= 10;} I wanna work for Microsoft!
Author
The following doesn''t work because _while_ requires a bool, not an int. or does this only work in C?
Thanks,
Scott
Email
Website
"If you try and don''t succeed, destroy all evidence that you tried."
int i = 123456; // integerint s = 0; // sumwhile(i){ s += (i % 10); i /= 10;} Thanks,
Scott
Website
"If you try and don''t succeed, destroy all evidence that you tried."
quote:Original post by wojtos
..._while_ requires a bool, not an int.
Just for further reference, all C/C++ conditional simply require an expression that evaluates to zero or non-zero. This has interesting implications when you iterate and decrement a variable: if the variable somehow successfully drops below zero, the loop will never end (which is why it''s actually a good idea to use i>0).
The same applies to if-conditionals.
I wanna work for Microsoft!
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