hi,

i was reading this code

Can you try to Run this code first & if it works in right way(Working properly) please explain to me it !!!

from sys import exit

def gold_room():
    print "This room is full of gold.  How much do you take?"

    choice = raw_input("> ") #ask the user !
    if "0" in choice or "1" in choice:
        how_much = int(choice)
    else:
        dead("Man, learn to type a number.")

    if how_much < 50:
        print "Nice, you're not greedy, you win!"
        exit(0)
    else:
        dead("You greedy bastard!")


def dead(why):
    print why, "Good job!"
    exit(0)


        
gold_room()

Thanks

Hi there.

This code is really simple, tell us explicitly which line do you have trouble understanding? raw_input? int()? if else? def? We cannot help you that way, and it's not the first time you know.

And yeah it works, it's copy-pasted from some tutorial if I recall.

it will run & i know it is simple but why when i type 55

the result:

Man, learn to type a number. Good job! (why i get this result )

why i the result not dead("You greedy bastard!")

Sorry Lysy but when i type the numbers i get many questions

    if "0" in choice or "1" in choice:
        how_much = int(choice)
    else:
        dead("Man, learn to type a number.")

That is a correct result for your input. Study this if-else clause, google/bing on what type raw_input returns, and how does 'in' keyword works on whatever type the 'choice' variable is.

it will run & i know it is simple but why when i type 55
the result:
Man, learn to type a number. Good job! (why i get this result )
why i the result not dead("You greedy bastard!")
Sorry Lysy but when i type the numbers i get many questions

if "0" in choice or "1" in choice:
    how_much = int(choice)
else:
    dead("Man, learn to type a number.")

the first line in that part checks if the text you've entered contains "0" or "1" , if it does it will try to convert the text to a number and assign it to the how_much variable , it the text doesn't contain 0 or 1 it will run the dead function with "Man, learn to type a number." as its parameter.

"55" doesn't contain 0 or 1 so it will run the dead function which prints the parameter "Man, learn to type a number." followed by "Good job!" and then it exits.

I know that but

else:
dead("You greedy bastard!")

55 isn't less than 50 so why we don't get dead("You greedy bastard!")

how it works ?

sorry for hard understanding

Thanks all

55 isn't less than 50 so when we don't get dead("You greedy bastard!")

def dead(why):
    print why, "Good job!"
    exit(0)

exit(0) ends up a script.

Please, read code first, google/bing it later.

if "0" in choice or "1" in choice:
        how_much = int(choice)
    else:
        dead("Man, learn to type a number.")

if "0" in choice or "1" in choice:
        how_much = int(choice)
    else:
        dead("Man, learn to type a number.")

try:
    how_much = int(choice)
except ValueError:
    print("Man, learn to type a number!")
    exit(0)

Lysy i read the code!!

ok i need answer for this question to be sure !

Try to type 100 you will get
You greedy bastard! Good job!
that's mean
else:
dead("You greedy bastard!")
& i should get that
if "0" in choice or "1" in choice:
how_much = int(choice)

Sorry for hard understanding

Thanks