Lighting Question

Abstract Thought · 2001-11-14T19:37:58

I doing my own transformation and lighting, the transformation works, but I not so sure about the lighting. My results look great and seem to follow the laws of physics, but do they really? If you shine a bright red light on a gray cube, what color would the reflected light be? If you shine another light, bright blue, what would their combined reflected light be? What if the cube is black, or bright white, or a mix of colors. Please have a look at my lighting code and tell me what you think. int CubeColor[3]={128,128,128}; //int CubeColor[3]={0,0,0}; //int CubeColor[3]={255,255,255}; //int CubeColor[3]={128,255,128}; int LightColor1[3]={0,0,255}; int LightColor2[3]={255,0,0}; float angle1 = DotProduct(LightNormalObjectSpace1,StreamSource[i].normal); if(angle1<0) angle1=0; if(angle1>1) angle1=1; float angle2 = DotProduct(LightNormalObjectSpace2,StreamSource[i].normal); if(angle2<0) angle2=0; if(angle2>1) angle2=1; StreamDestination[i].diffuse = ((int(angle1*CubeColor[0])>>2)<<16); StreamDestination[i].diffuse += ((int(angle1*CubeColor[1])>>2)<<8); StreamDestination[i].diffuse += (int(angle1*CubeColor[2])>>2); StreamDestination[i].diffuse += ((int(angle1*LightColor1[0])>>2)<<16); StreamDestination[i].diffuse += ((int(angle1*LightColor1[1])>>2)<<8); StreamDestination[i].diffuse += (int(angle1*LightColor1[2])>>2); StreamDestination[i].diffuse += ((int(angle2*CubeColor[0])>>2)<<16); StreamDestination[i].diffuse += ((int(angle2*CubeColor[1])>>2)<<8); StreamDestination[i].diffuse += (int(angle2*CubeColor[2])>>2); StreamDestination[i].diffuse += ((int(angle2*LightColor2[0])>>2)<<16); StreamDestination[i].diffuse += ((int(angle2*LightColor2[1])>>2)<<8); StreamDestination[i].diffuse += (int(angle2*LightColor2[2])>>2); quote:Only by art can we get outside ourselves; instead of seeing only one world, our own, we see it under multiple forms. Edited by - Abstract Thought on November 9, 2001 1:47:57 PM

Math and Physics Programming

Started by Abstract Thought November 09, 2001 12:45 PM

10 comments, last by Abstract Thought 22 years, 5 months ago

Abstract Thought

122

Author

November 14, 2001 05:27 PM

quote: Original post by Black Marq: Perception of reality and observation of reality are really the same thing aren't they?

Are they?

With perception I can see the color red, but there really is no such thing as the color red.

With observation I can perceive the color red as photons or waves, but is there really such a thing as photons and waves, or am I still limited by my perception.

quote: To gaze is to think

Edited by - Abstract Thought on November 14, 2001 6:28:38 PM

Only by art can we get outside ourselves; instead of seeing only one world, our own, we see it under multiple forms.

Black Marq

210

November 14, 2001 07:36 PM

I don''t know I''ve been picking up a couple of used books on quantum physic and I still really don''t understand any of the theory or the math behind it all that well.

So I started working on sound frequency analysis in my spare time. I''m learning how to dissect sound with Fourier mathmatics, it seem alot easier then all that light theory stuff. Once I get handle on this stuff maybe I''ll move on to light to see if there anything in it for me.

Lighting Question

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Lighting Question

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