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passing variadic arguments

General and Gameplay Programming Programming

Started by lride March 05, 2015 12:05 AM

1 comment, last by lride 9 years, 1 month ago

lride

675

Author

March 05, 2015 12:05 AM


struct A
{
	A(){}
	A(int i, std::string s){}
	A(std::string  s){}
};

A createA(...)
{
	return A(...);

}

int main()
{
        createA();
	createA(1, "zz");
	createA("zz");
}

I'm getting error C2143: syntax error : missing ')' before '...'

why??

An invisible text.

Servant of the Lord

33,739

March 05, 2015 12:16 AM

What language are you using?

If C++, it needs to be a templated function, and you do it like this:


template<typename ...Args> //Take a variable number of template arguments.
A createA( Args&& ...args ) //Accept the variable number of arguments by 'universal reference' (const ref, ref, or rvalue ref).
{
	return A( std::forward<Args>(args)... ); //Forward their current reference type, and unroll the arguments.
}