& operator question
Author
#include
using namespace std;
// in main
char symbol = ''a'';
cout << &symbol << endl; //I don''t get the memory address
//of the location at witch symbol
//is placed in memory.
//Instead i get ''a'' on the screen.
I thought & operator always gives me the memory location of a
variable.
If I make array of characters and place the & operator
in front that variable (like above) I get the memory location.
Any ideas. Thanks in advance.
Remember a string of characters is accessed trough a pointer, so it is logical that if you feed a pointer to char to cout it will print the string, or more specific the memory from the pointed location until it finds a null character "\0", if you want to get the memory location you might have to do some casting before cout like so:
not sure if works, but something like that is what you have to do.
Edit:
oh yeah, there are some casting statements for cout, but I dont remember those, I think HEX,OCT,DEC or something, in any case I stick to good old trusty printf
Edited by - kwizatz on November 14, 2001 9:35:46 AM
// in mainchar symbol = 'a';int nMemorylocation = (int) &symbolcout << nMemorylocation << endl; not sure if works, but something like that is what you have to do.
Edit:
oh yeah, there are some casting statements for cout, but I dont remember those, I think HEX,OCT,DEC or something, in any case I stick to good old trusty printf
Edited by - kwizatz on November 14, 2001 9:35:46 AM
quote:Original post by superpeter
void main(){
char* symbol = "b";
cout << &symbol << endl;
}
That outputs the address of the pointer to the "b", not the address of the "b".
Author
Thanks for the replies.
Now I have this...
char symbol= ''a'';
char s[] = "a";
int nMemorylocation = (int) &symbol
cout << nMemorylocation << endl; //6553091, I non valid location
cout << &s << endl; //0063FE01, a valid location
I know when doing char s[]="a" I am making a string of
characters. And I can retrieve the memory location of the
first character in this string with &S.
But when I want do retrieve the memory location of the first and only character in the character variable "symbol", I do not get
a valid memory address (I might be wrong though).
Again thanks for the replies. All comments are helpful.
Now I have this...
char symbol= ''a'';
char s[] = "a";
int nMemorylocation = (int) &symbol
cout << nMemorylocation << endl; //6553091, I non valid location
cout << &s << endl; //0063FE01, a valid location
I know when doing char s[]="a" I am making a string of
characters. And I can retrieve the memory location of the
first character in this string with &S.
But when I want do retrieve the memory location of the first and only character in the character variable "symbol", I do not get
a valid memory address (I might be wrong though).
Again thanks for the replies. All comments are helpful.
#include <iostream>using namespace std;int main(int argc, char *argv[]){ char *a = "a"; int &address = (int &)(*a); cout << "Character: " << a << endl << "Address: 0x" << &address << endl; return 0;}
Or instead of storing an extra integer, just cast the pointer to a void pointer, then no special processing will be done:
main
{
char symbol = ''b'';
cout (void *)&symbol << endl;
}
main
{
char symbol = ''b'';
cout (void *)&symbol << endl;
}
FrikkaSoft: you might want to learn you''re hexadecimal to decimal conversion.
6553091 = 0x0063fe03.
6553091 = decimal.
0x0063fe03 = hex.
To the vast majority of mankind, nothing is more agreeable than to escape the need for mental exertion... To most people, nothing is more troublesome than the effort of thinking.
6553091 = 0x0063fe03.
6553091 = decimal.
0x0063fe03 = hex.
To the vast majority of mankind, nothing is more agreeable than to escape the need for mental exertion... To most people, nothing is more troublesome than the effort of thinking.
Author
I know, I am extremely ashamed in the moment
I think my effort of thinking was lacking during that post by Kwizatz. Well...
Batnandi mönnum er best að lifa.
I think my effort of thinking was lacking during that post by Kwizatz. Well...
Batnandi mönnum er best að lifa.
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