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What is the output?

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I tried to debug the following code "on paper" (without compiler/debugger),but it seems that is not possible because of the pointers.

#include <stdio.h>

#define MAX 10
int main()
    char array[MAX][MAX], c = 0;
    int d = 1, x = 0, i, j;
        scanf("%s", array[x]);
    while (array[x++][0] != '0');

        float* pf;
        int xx, *pi = (int*)&array[0][7];
        xx = ((*pi) & 0x41000000);
        pf = (float*)&xx;
        printf("%5.2f\n", *pf);
    for (c- = --x; c++ & **array; d+=!(c << x > 0)) 
    d -= c;
    for (i = 0; i < x; i == 1 ? printf("%c ", array[i][x >> 1]):i, ++i)
        for (j = 0; j <= x - i; printf("%c", array[i][j++]));
    printf("%x", d);
    return 0;

//Example input:

programming languages 0

prolaa 6

Could someone explain this code?


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Why is that not possible?

Draw each variable as a rectangle at the paper, write its value in the rectangle (and for ease of reference, write the name of the variable next to the rectangle).
Pointers are rectangles that have an arrow from inside their rectangle pointing to another rectangle.

int i = 10; // Draw a rectangle, write 10 inside, write 'i' next to it.
int *p = &i; // Draw a rectangle, draw an arrow from the center of that rectangle pointing to the 'i' rectangle, write 'p' next to it.

Good luck with your home work!

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