# Is my math right?

This topic is 509 days old which is more than the 365 day threshold we allow for new replies. Please post a new topic.

## Recommended Posts

If I have an object that accelerates from 0 to X, I want to know what it's speed will be by the time it covers a certain amount of ground.

So:

function for time it takes to accelerate to a certain speed:

t = s/a, where s = speed, a = acceleration.

function for speed / time: s = t

space needed to accelerate to a certain speed = 1/2 (s/a)2,

dist = s2/2a2

s2 = 2a2  * dist

s = sqrt(2*dist)*a

So, this way, I can get the speed from the distance travelled. Is this correct?

I'm having some problems, so I'm wondering if the math for this is incorrect, or if it's something else.

##### Share on other sites
X = 1/2 * a * t ^ 2
V = a * t -> t = V / a

// Looks like you dropped an 'a' here
X = 1/2 * a * (V / a) ^ 2 = 1/2 * V^2 / a
2 * a * X = V^2

And the result
V = sqrt(2 * a * X);

Edited by HappyCoder

##### Share on other sites

Thanks HappyCoder! That makes sense. I hadn't thought of getting the integral of the function for velocity, only the one for time.

1. 1
2. 2
Rutin
22
3. 3
JoeJ
18
4. 4
5. 5

• 17
• 40
• 23
• 13
• 13
• ### Forum Statistics

• Total Topics
631726
• Total Posts
3001910
×